假设我有 :items 与 has_many 与 :properties 关联,那么我可以像这样搜索具有名称为 'a_name' 和值 'a_value' 的属性的所有项目
q: { properties_name_eq: 'a_name', properties_value_eq: 'a_value' }
现在,如果我想搜索具有名称为“a_name”和值“a_value”的属性以及名称为“another name”和值“another value”的属性的所有项目,该怎么办?
以下不起作用,因为它仅加入属性表一次
q: {
g: {
'0' => { properties_name_eq: 'a_name', properties_value_eq: 'a_value' },
'1' => { properties_name_eq: 'another_name', properties_value_eq: 'another_value'}
}
}
生成的 SQL 看起来像这样
SELECT DISTINCT "items".* FROM "items"
LEFT OUTER JOIN "properties" ON "properties"."item_id" = "items"."id"
INNER JOIN ((SELECT "items".* FROM "items")) AS sel_111 on sel_111.id
WHERE
(("properties"."name" = 'a_name' AND "properties"."value" = 'a_value') AND ("properties"."name" = 'another_name' AND "properties"."value" = 'another_value'))
EDIT:
为了更清楚地说明我想要什么,我将在下面粘贴一个规范。
Item.create name: 'ab', properties_attributes: [{ name: 'a', value: 'a1'}, {name: 'b', value: 'b1'}]
Item.create name: 'a', properties_attributes: [{ name: 'a', value: 'a1'}]
Item.create name: 'b', properties_attributes: [{name: 'b', value: 'b1'}]
Item.create name: 'ax', properties_attributes: [{ name: 'a', value: 'a1'}, {name: 'b', value: 'x'}]
Item.create name: 'bx', properties_attributes: [{ name: 'a', value: 'x'}, {name: 'b', value: 'b1'}]
Item.create name: 'other', properties_attributes: [{ name: 'other', value: '123'}]
get :index, q: { properties_name_eq: 'a', properties_value_eq: 'a1' }
names = JSON.parse(response.body).map{|u| u['name']}
expect(names).to match_array ['ab', 'a', 'ax'] # OK!
get :index,
q: {
m: 'or',
g: {
'0' => { properties_name_eq: 'a', properties_value_eq: 'a1' },
'1' => { properties_name_eq: 'b', properties_value_eq: 'b1'}
}
}
names = JSON.parse(response.body).map{|u| u['name']}
expect(names).to match_array ['ab'] #FAILS!