我有这段代码打印：
[( ?Random = <http://www.semanticweb.org/vassilis/ontologies/2013/5/Test#Hello> ), ( ?Random = <http://www.semanticweb.org/vassilis/ontologies/2013/5/Test#Bye> )]
我尝试在 [#] 处拆分，但没有成功。
我应该在 split 中放入什么，以便我只能得到 # 之后的部分：你好，再见
Query query = QueryFactory.create(queryString);
QueryExecution qe= QueryExecutionFactory.create(query, model);
ResultSet resultset = qe.execSelect();
ResultSet results = ResultSetFactory.copyResults(resultset);
final ResultSet results2 = ResultSetFactory.copyResults(results);
System.out.println( "== Available Options ==" );
ResultSetFormatter.out(System.out, results, query);
Scanner input = new Scanner(System.in);
final String inputs;
inputs = input.next();
final String[] indices = inputs.split("\\s*,\\s*");
final List<QuerySolution> selectedSolutions = new ArrayList<QuerySolution>(
indices.length) {
{
final List<QuerySolution> solutions = ResultSetFormatter
.toList(results2);
for (final String index : indices) {
add(solutions.get(Integer.valueOf(index)));
}
}
};
System.out.println(selectedSolutions);
如果我理解正确，您只想通过正则表达式从输入字符串中提取“Hello”和“Bye”。
在这种情况下，我只会使用两者之间的迭代匹配# and >， 像这样：
// To clarify, this String is just an example
// Use yourScannerInstance.nextLine to get the real data
String input = "[( ?Random = <http://www.semanticweb.org/vassilis/ontologies/2013/5/Test#Hello> ), "
+ "( ?Random = <http://www.semanticweb.org/vassilis/ontologies/2013/5/Test#Bye> )]";
// Pattern improved by Brian
// was: #(.+?)>
Pattern p = Pattern.compile("#([^>]+)>");
Matcher m = p.matcher(input);
// To clarify, printing the String out is just for testing purpose
// Add "m.group(1)" to a Collection<String> to use it in further code
while (m.find()) {
System.out.println(m.group(1));
}
Output:
Hello
Bye
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