如何在 bash 中排除打印仅具有父路径的行并排除所有子目录路径

团队，我问了这个问题的反面，并在这里得到了回答。与其他类似路径相比，如何排除在 bash 中打印没有子目录路径的行？ https://stackoverflow.com/questions/76040169/how-to-exclude-printing-in-bash-a-line-that-has-no-sub-directory-path-compared-t/76041373#76041373

在这个问题上我想做相反的事情。

我想要下面这个的相反。

cat file | sort | tac |awk '{sub("/[^/]+$","")} index(prev,$0"/") != 1{print} {prev=$0}'

where file实际上代表了a的输出find命令：

find src/services/ -type f -name 'BUILD.bazel'

所以包含：

$ cat file
src/services/sam-agent/BUILD.bazel
src/services/sam-agent/auth/BUILD.bazel
src/services/sam-agent/certs/BUILD.bazel
src/services/sam-agent/server/BUILD.bazel
src/services/jam-controller/BUILD.bazel
src/services/jam-controller/api/BUILD.bazel
src/services/jam-controller/client/BUILD.bazel
src/services/wam-controller/api/BUILD.bazel
src/services/wam-controller/api/client/BUILD.bazel
src/services/wam-controller/api/server/BUILD.bazel

在上述输入上运行时所需的命令应输出

src/services/sam-agent
src/services/jam-controller
src/services/wam-controller

即预期仅打印父目录而没有子目录：

src/services/sam-agent #< should be printed
src/services/sam-agent/auth
src/services/sam-agent/certs
src/services/sam-agent/server
src/services/jam-controller #< should be printed
src/services/jam-controller/api
src/services/jam-controller/client
src/services/wam-controller/api #< should obe printed
src/services/wam-controller/api/client
src/services/wam-controller/api/server

尝试了答案1并得到了下面的答案。仍然显示子目录，而不仅仅是src/services/rams

cat /tmp/t.log | sort | tac | awk '{if ($0 in seen) print; else {sub("/[^/]+$", ""); seen[$0]}}'

src/services/rams/store/postgres
src/services/rams

样本t.log

src/services/rams
src/services/rams/integration
src/services/rams/keys
src/services/rams/migrations
src/services/rams/mocks
src/services/rams/server
src/services/rams/smoke
src/services/rams/store
src/services/rams/store/postgres
src/services/rams/store/postgres/mocks
src/services/rams/tools/keyrotate
src/services/rams/tools/secretmanager
src/services/rams/vault

请您尝试以下操作：

cat file | sort | awk 'index($0, prev"/") != 1 {print; prev = $0}'

Replace cat file with find src/services/ -type f -name 'BUILD.bazel'.

• 输入已排序，因此父路径首先出现。
• index($0, prev"/")回报1 if prev"/"是一个子串 的$0， 意义$0是一个孩子prev。如果没有，则打印$0作为父母。
• 尾随的/ in prev"/"锚定字符串以避免伪匹配。
• 变量prev已更新only if $0是一位家长。