我正在尝试对整个列执行操作，但出现类型错误，我想创建一个包含匀称点 https://shapely.readthedocs.io/en/latest/manual.html#points:
crime_df = crime_df[crime_df['Latitude'].notna()]
crime_df = crime_df[crime_df['Longitude'].notna()]
crime_df['Longitude'] = crime_df['Longitude'].astype(float)
crime_df['Latitude'] = crime_df['Latitude'].astype(float)
print (crime_df['Longitude'])
print (crime_df['Latitude'])
crime_df['point'] = Point(crime_df['Longitude'], crime_df['Latitude'])
Output:
18626 -87.647379
Name: Longitude, Length: 222, dtype: float64
18626 41.781100
Name: Latitude, Length: 222, dtype: float64
TypeError: cannot convert the series to <class 'float'>
我认为你需要分别处理每一点，所以需要DataFrame.apply http://pandas.pydata.org/pandas-docs/stable/reference/api/pandas.DataFrame.apply.html使用 lambda 函数：
crime_df['point'] = crime_df.apply(lambda x: Point(x['Longitude'], x['Latitude'], axis=1)
或者谢谢@N。沃达：
crime_df["point"] = crime_df[["Longitude", "Latitude"]].apply(Point, axis=1)
或者列表理解替代方案是：
crime_df['point'] = [Point(lon, lat)
for lon, lat in crime_df[['Longitude','Latitude']].values]
编辑：我认为矢量化方式是可以使用的geopandas.points_from_xy https://geopandas.readthedocs.io/en/latest/gallery/create_geopandas_from_pandas.html like:
gdf = geopandas.GeoDataFrame(df,geometry=geopandas.points_from_xy(df.Longitude,df.Latitude))
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