我们如何验证函数内的方法是否被调用？
我这里有一个示例代码。
class MockService extends Mock implements Service {}
class MockRepository extends Mock implements Repository {}
class Repository {
Repository({
required this.service,
});
final Service service;
Future<void> somethingFancy() async {
await service.doSomething();
}
}
class Service {
Future<void> doSomething() async {}
}
void main() {
final service = MockService();
final repository = Repository(service: service);
group('auth repository test', () {
test('test name', () async {
when(repository.somethingFancy).thenAnswer((_) => Future.value());
await repository.somethingFancy();
verify(service.doSomething).called(1);
});
});
}
如果我运行测试，我会收到此错误：
type 'Null' is not a subtype of type 'Future<void>'
test/auth_repository_test.dart 20:16 MockService.doSomething
test/auth_repository_test.dart 15:19 Repository.registerUser
package:mocktail/src/mocktail.dart 210:8 when.<fn>
test/auth_repository_test.dart 29:11 main.<fn>.<fn>
===== asynchronous gap ===========================
dart:async _completeOnAsyncError
package:mocktail/src/mocktail.dart 210:8 when.<fn>
test/auth_repository_test.dart 29:11 main.<fn>.<fn>
如果我将存储库变量更改为final repository = MockRepository();,
我无法注射Service class，所以服务类中的方法肯定不会被调用。这就是为什么我运行这个测试：
void main() {
final service = MockService();
final repository = MockRepository();
group('auth repository test', () {
test('test name', () async {
when(repository.somethingFancy).thenAnswer((_) => Future.value());
await repository.somethingFancy();
verify(service.doSomething).called(1);
});
});
}
我收到一条错误消息no matching calls
No matching calls (actually, no calls at all).
(If you called `verify(...).called(0);`, please instead use `verifyNever(...);`.)
package:test_api fail
package:mocktail/src/mocktail.dart 722:7 _VerifyCall._checkWith
package:mocktail/src/mocktail.dart 515:18 _makeVerify.<fn>
test/auth_repository_test.dart 32:13 main.<fn>.<fn>
我在这里做错了什么？感谢这么多的帮助。
您在测试中使用了错误的方法。
你必须模拟答案Service#doSomething代替Repository#doSimethingFancy。检查你的when陈述。
test('test name', () async {
when(service.doSomething()).thenAnswer((_) => Future.value());
await repository.somethingFancy();
verify(service.doSomething).called(1);
});
本文内容由网友自发贡献，版权归原作者所有，本站不承担相应法律责任。如您发现有涉嫌抄袭侵权的内容，请联系:hwhale#tublm.com(使用前将#替换为@)
