我正在尝试使用 Tkinter 制作一个基本的 GUI,并使用网格管理器在标签旁边有一个输入框,但是如果我将 .grid() 与 Entry 对象一起使用,则当我运行程序时,该窗口不会显示。
当我使用 .pack() 时它确实有效,这很奇怪,因为我听说当我在同一个小部件中有其他东西使用 .grid() 时不要使用 .pack() 。但我确实想使用 .grid() 因为我希望能够按照我想要的方式组织它。
代码如下,我在使用 Entry 对象 showName 时遇到问题。注释掉的 .pack() 语句是有效的, .grid() 语句是无效的。
有人知道这是怎么回事吗?
from Tkinter import *
class RenamerGUI():
def __init__(self, master):
frame = Frame(master)
frame.pack() #Make frame visible
self.exit = Button(frame, text = "Exit", fg = "red", command = frame.quit)
self.csv2tsv = Button(frame, text = "csv2tsv", fg = "green", bg = "black", command=self.csv2tsv)
self.epguidestsvFormatter = Button(frame, text = "epguidestsvFormatter", fg = "green", bg = "black", command = self.epguidestsvFormatter)
self.epNamesList = Button(frame, text = "epNamesList", fg = "green", bg = "black", command = self.epNamesList)
self.SeasonSplitter = Button(frame, text = "SeasonSplitter", fg = "green", bg = "black", command = self.SeasonSplitter)
self.Renamer = Button(frame, text = "Renamer", fg = "green", bg = "black", command = self.Renamer)
self.showLabel = Label(frame, text = "Show: ")
self.showName = Entry(master)
self.get = Button(frame, text = "Get", command = self.textgetter)
self.exit.grid(row=3, column=4)
self.csv2tsv.grid(row=1, column = 0)
self.epguidestsvFormatter.grid(row=1, column=1)
self.epNamesList.grid(row=1, column=2)
self.SeasonSplitter.grid(row=1, column=3)
self.Renamer.grid(row=1, column=4)
self.showLabel.grid(row=2)
self.showName.grid(row=2, column=1)
#self.showName.pack(side=BOTTOM)