您可以使用序列分配来复制指向的对象(而不是分配给p.contents
,这会改变指针值):
def copy(dst, src):
"""Copies the contents of src to dst"""
pointer(dst)[0] = src
# alternately
def new_copy(src):
"""Returns a new ctypes object which is a bitwise copy of an existing one"""
dst = type(src)()
pointer(dst)[0] = src
return dst
# or if using pointers
def ptr_copy(dst_ptr, src_ptr):
dst_ptr[0] = src_ptr[0]
ctypes
将为您进行类型检查(这并非万无一失,但总比没有好)。
使用示例,并验证它确实有效;):
>>> o1 = Point(1, 1)
>>> o2 = Point(2, 2)
>>> print (o1.x, o1.y, addressof(o1)), (o2.x, o2.y, addressof(o2))
(1, 1, 6474004) (2, 2, 6473524)
>>> copy(o2, o1)
>>> pprint (o1.x, o1.y, addressof(o1)), (o2.x, o2.y, addressof(o2))
(1, 1, 6474004) (1, 1, 6473524)
>>> o1 = Point(1, 1), o2 = Point(2, 2)
>>> print (o1.x, o1.y, addressof(o1)), (o2.x, o2.y, addressof(o2))
(1, 1, 6473844) (2, 2, 6473684)
>>> p1, p2 = pointer(o1), pointer(o2)
>>> addressof(p1.contents), addressof(p2.contents)
(6473844, 6473684)
>>> ptr_copy(p1, p2)
>>> print (o1.x, o1.y, addressof(o1)), (o2.x, o2.y, addressof(o2))
(2, 2, 6473844) (2, 2, 6473684)
>>> addressof(p1.contents), addressof(p2.contents)
(6473844, 6473684)