举例来说,我有一个名为 RunnableA 的 Runnable,它可以执行某些操作。我还有一个名为 RunnableB 的 Runnable,它可以执行其他操作。有没有办法可以将这两个 Runnable 组合起来,以便它们在同一个线程中运行?
问题的第二部分是如果这可能的话,我可以指定它们运行的顺序吗?
编辑!:我想这样做的原因是因为我需要在 EDT 上运行代码,但其他一些代码需要在另一个线程上运行。请看下面的代码。
像这样的东西
public final class CompoundRunnable implements Runnable
{
private final Iterable runnables;
public CompoundRunnable(Iterable runnables)
{
// From Guava. Easy enough to do by hand if necessary
this.runnables = Lists.newArrayList(runnables);
}
public CompoundRunnable(Runnable... runnables)
{
this(Arrays.asList(runnables));
}
@Override
public void run()
{
for (Runnable runnable : runnables)
{
runnable.run();
}
}
}
public void setStatusAndProgress(final String status,Runnable runnable)
{
Runnable startUpRunner = new Runnable()
{
public void run()
{
SwingUtilities.invokeLater(new Runnable()
{
public void run()
{
setStatus(status);
selfReference.getProgressBar().setIndeterminate(true);
}
});
}
};
Runnable cleanUpRunner = new Runnable()
{
public void run()
{
SwingUtilities.invokeLater(new Runnable()
{
public void run()
{
setStatus("");
getProgressBar().setIndeterminate(false);
}
});
}
};
Runnable theRunner = new CompoundRunnable(startUpRunner,runnable,cleanUpRunner);
new Thread(theRunner).start();
}
抱歉,如果这没有得到很好的解释,如果您需要澄清,请发表评论。
Thanks!
那么你当然可以创建一个Runnable
它只运行一个可运行程序,然后运行另一个:
public final class CompoundRunnable implements Runnable
{
private final Runnable first;
private final Runnable second;
public CompoundRunnable(Runnable first, Runnable second)
{
this.first = first;
this.second = second;
}
@Override
public void run()
{
first.run();
second.run();
}
}
更一般地说,您可以让它花费Iterable<Runnable>
,复制所有Runnable
参考,然后按顺序运行它们。例如:
public final class CompoundRunnable implements Runnable
{
private final Iterable<Runnable> runnables;
public CompoundRunnable(Iterable<Runnable> runnables)
{
// From Guava. Easy enough to do by hand if necessary
this.runnables = Lists.newArrayList(runnables);
}
public CompoundRunnable(Runnable... runnables)
{
this(Arrays.asList(runnables));
}
@Override
public void run()
{
for (Runnable runnable : runnables)
{
runnable.run();
}
}
}
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