我尝试使用以下函数（node.js v8）：
exports.sendComNotification = functions.firestore
.document('Comunicados/{comID}')
.onUpdate((snap, context) => {
console.log('Com triggered');
const newValue = snap.after.data();
const msg = newValue.title;
var message = {
notification: {
title: 'Comunicado da Diretoria!',
body: msg,
badge: '1',
sound: 'default',
click_action: 'FLUTTER_NOTIFICATION_CLICK',
},
topic: "Comunicados"
};
return admin.messaging().send(message)
.then((response) => {
console.log('Successfully sent message:', response);
return
})
.catch((error) => {
console.log('Error sending message:', error);
return
});
});
但这会在函数日志中出现以下错误：
Error sending message: {
Error: Invalid JSON payload received.Unknown name "badge"
at 'message.notification': Cannot find field.
Invalid JSON payload received.Unknown name "sound"
at 'message.notification': Cannot find field.
Invalid JSON payload received.Unknown name "click_action"
at 'message.notification': Cannot find field.
at FirebaseMessagingError.FirebaseError[as constructor](/srv/node_modules / firebase - admin / lib / utils / error.js: 42: 28)
如果我取出“badge”、“sound”和“click_action”，它会起作用，但是接收时没有声音，并且 onResume （flutter 应用程序）中定义的操作当然也不会触发。设置声音和 click_action 属性的正确方法是什么？提前致谢。
好吧，我终于设法到处收集零碎的东西以使其发挥作用。不明白为什么文档没有明确且直接的路径来实现这种常见的要求。
exports.sendComNotification = functions.firestore
.document('Comunicados/{comID}')
.onCreate((snap, context) => {
const doc = snap.data();
const msg = doc.title;
var message = {
notification: {
title: 'Comunicado da Diretoria!',
body: msg
},
data: {
title: 'Comunicado',
body: msg
},
android: {
notification: {
sound: 'default',
click_action: 'FLUTTER_NOTIFICATION_CLICK',
},
},
apns: {
payload: {
aps: {
badge: 1,
sound: 'default'
},
},
},
topic: "Comunicados"
};
return admin.messaging().send(message)
.then((response) => {
console.log('Successfully sent message:', response);
return
})
.catch((error) => {
console.log('Error sending message:', error);
return
});
});
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