vb6中动态两级或多级子菜单生成

朋友们， 告诉我怎么做生成1级以上的子菜单在VB6中运行时？简单解释一下？有什么具体的控制措施吗？但我不想使用外部控件！

您可以使用API​​函数创建多级子菜单

Private Declare Function CreatePopupMenu Lib "user32" () As Long

Private Declare Function AppendMenu Lib "user32" Alias "AppendMenuA" (ByVal hmenu As Long, ByVal wFlags As Long, ByVal wIDNewItem As Long, ByVal lpNewItem As Any) As Long

Private Declare Function GetCursorPos Lib "user32" (lpPoint As POINTAPI) As Long

Private Declare Function TrackPopupMenu Lib "user32" (ByVal hmenu As Long, ByVal wFlags As Long, ByVal X As Long, ByVal Y As Long, ByVal nReserved As Long, ByVal hwnd As Long, lprc As Any) As Long

Private Declare Function DestroyMenu Lib "user32" (ByVal hmenu As Long) As Long

Private Type POINTAPI
    X As Long
    Y As Long
End Type

Dim hmenu As Long, hSubMenu As Long
Private Const MF_STRING = &H0&
Private Const MF_SEPARATOR = &H800&
Private Const MF_POPUP = &H10&

  hSubMenu = CreatePopupMenu
  AppendMenu hSubMenu, 0, 121, "Sub Menu1"
  AppendMenu hSubMenu, 0, 122, "Sub Menu2"
  
  hmenu = CreatePopupMenu
  AppendMenu hmenu, 0, 107, "Menu1"
  
  AppendMenu hmenu, 0, 106, "Menu2"
  
  AppendMenu hmenu, MF_POPUP, hSubMenu, "Menu3"
  AppendMenu hmenu, MF_POPUP, hSubMenu, "Menu4"
  
  AppendMenu hmenu, 0, 101, "Menu5"

显示

  If Button = vbRightButton Then
    Dim P As POINTAPI
    GetCursorPos P
    TrackPopupMenu hmenu, 0, P.X, P.Y, 0, hwnd, 0

菜单不会显示，直到TrackPopupMenu叫做。它的返回值可以指示选择了哪个（如果有）菜单项。例如，如果选择“Menu1”，它可能返回“107”。