我正在尝试创建一个员工数据库(员工向量)。有 3 种类型的员工,即。 Employees 是基类,Manager、Engg 和 Scientist 是派生类。
每个员工都有名字和姓氏。除了名字之外,这 3 种类型的员工中的每一种都有独特的统计数据,即。经理每周有多少次会议,而工程师则有工作经验等等。
我有一些问题
1. 我应该将派生对象向上转换为基类还是将基类向下转换为派生类?
2.如何使用多态性来重写方法,因为我希望用户添加员工类型,并根据所选类型显示相应的输入字段,即。如果是经理,除了名字和姓氏之外,该计划还应该询问每周举行的会议?
这是我的班级文件
class Employee{
public:
Employee();
Employee(string fName, string lName, int sal);
virtual void printEmp();
string getFirstName();
string getLastName();
protected:
string m_fName;
string m_lName;
int m_sal;
};
class Manager : public Employee{
public:
Manager();
Manager(string fName, string lName, int sal, int meets, int hols);
void printEmp();
protected:
int m_meets;
int m_hols;
};
这是实现
Employee::Employee(){
m_fName = "Default";
m_lName = "Default";
m_sal = 0;
}
Employee::Employee(string fName, string lName, int sal){
m_fName = fName;
m_lName = lName;
m_sal = sal;
}
void Employee::printEmp(){
cout << "First Name: " << m_fName << endl
<< "Last Name: " << m_lName << endl
<< "Salary: " << m_sal << endl;
}
string Employee::getLastName(){
return m_lName;
}
string Employee::getFirstName(){
return m_fName;
}
Manager::Manager(string fName, string lName, int sal, int meets, int hols) : Employee(fName, lName, sal), m_meets(meets), m_hols(hols)
{
//empty
}
void Manager::printEmp(){
Employee::printEmp();
cout << "Meets/Week: " << m_meets << endl
<< "Holidays/Year: " << m_hols << endl << endl;
这是主要的
int main(){
bool exit = false;
vector<Employee*> dBVector;
while (!exit){
cout << "Welcome to Employee Database, Enter an option to continue..." << endl;
cout << "1) Add an Employee, 2) Delete an Employee, 3) Save Database, 4) Exit" << endl;
int input;
cin >> input;
string fNameInp;
string lNameInp;
int salInp;
string lNameSearch;
int i; // for loop in Delete employee case
bool deleted = false;
switch (input){
case 1: //Add
cout << "1) Add a Manager, 2) Add an Engg, 3) Add a Researcher" << endl;
int empInput;
cin >> empInput;
if (empInput == 1){
cout << "Enter First Name: ";
cin >> fNameInp;
cout << "Enter Last Name: ";
cin >> lNameInp;
cout << "Enter Salary: ";
cin >> salInp;
cout << "Number of meetings/week: ";
int meetsInp;
cin >> meetsInp;
cout << "Number of holidays/year: ";
int holsInp;
cin >> holsInp;
Manager mEmp(fNameInp, lNameInp, salInp, meetsInp, holsInp);
Employee &emp = mEmp;
dBVector.push_back(&mEmp);
dBVector[dBVector.size()-1]->printEmp();
}
else if (empInput == 2){
cout << "Enter First Name: ";
cin >> fNameInp;
cout << "Enter Last Name: ";
cin >> lNameInp;
cout << "Enter Salary: ";
cin >> salInp;
cout << "Cpp Experience (Y/N): ";
string cppInp;
cin >> cppInp;
cout << "Years of experience: ";
float expInp;
cin >> expInp;
cout << "Engg Type (Chem, Mech, IT): ";
string typInp;
cin >> typInp;
Engg eEmp(fNameInp, lNameInp, salInp, cppInp, expInp, typInp);
Employee &emp = eEmp;
dBVector.push_back(&eEmp);
dBVector[dBVector.size() - 1]->printEmp();
}
else if (empInput == 3){
cout << "Enter First Name: ";
cin >> fNameInp;
cout << "Enter Last Name: ";
cin >> lNameInp;
cout << "Enter Salary: ";
cin >> salInp;
cout << "School of PhD: ";
string schoolInp;
cin >> schoolInp;
cout << "Topic of PhD: ";
string topImp;
cin >> topImp;
Researcher rEmp(fNameInp, lNameInp, salInp, schoolInp, topImp);
Employee &emp = rEmp;
dBVector.push_back(&rEmp);
dBVector[dBVector.size() - 1]->printEmp();
}
break;
case 2: // Delete Emp
for (int x = 0; x < dBVector.size(); x++){
dBVector[x]->getLastName();
cout << endl;
}
cout << "Input Last name of the employee to delete: " << endl;
cin >> lNameSearch;
for (i = 0; i < dBVector.size(); i++){
if (dBVector[i]->getLastName() == lNameSearch){
dBVector.erase(dBVector.begin() + i);
cout << dBVector[i]->getFirstName() << "has been deleted from database";
deleted = true;
break;
}
}
if (deleted == false && i == dBVector.size()){
cout << "No Employee with Last Name - " << lNameSearch << " exists in Database." << endl;
}
else
break;
case 3: //save
cout << "saving..." << endl;
break;
case 4: //exit
exit = true;
break;
}
}
}
Please Help!