Common Lisp 中的（随机）不那么随机？

好的，最后一个问题，我将用 Common Lisp 完成我的猜数游戏！ :D 每当游戏开始（或者在第一个游戏之后开始新游戏）时，都会调用以下函数。

;;; Play the game
(defun play ()
    ;; If it's their first time playing this session,
    ;; make sure to greet the user.
    (unless (> *number-of-guesses* 0)
        (welcome-user))
    ;; Reset their remaining guesses
    (setq *number-of-guesses* 0)
    ;; Set the target value
    (setq *target*
        ;; Random can return float values,
        ;; so we must round the result to get
        ;; an integer value.
        (round
            ;; Add one to the result, because
            ;; (random 100) yields a number between
            ;; 0 and 99, whereas we want a number
            ;; from 1 to 100 inclusive.
            (+ (random 100) 1)))
    (if (eql (prompt-for-guess) t)
        (play)
        (quit)))

所以据说，每次玩家开始游戏时，*target*应设置为 1-100 之间的新随机整数。然而，每一次，*target*默认为 82。我该如何制作(random)随机行动？

您需要在程序开始时播种随机状态。

(setf *random-state* (make-random-state t))
;; # this initializes the global random state by
;;   "some means" (e.g. current time.)