这就是我想做的
class BaseClass(object):
successify = lambda x: "<Success>%s</Success>" % x
errorify = lambda x: "<Error>%s</Error>" % x
def try1(self):
print successify("try1")
def try2(self):
print self.successify("try2")
但这两种方法似乎都不起作用。
>>> BaseClass().try1()
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
File "<stdin>", line 5, in try1
NameError: global name 'successify' is not defined
>>> BaseClass().try2()
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
File "<stdin>", line 7, in try2
TypeError: <lambda>() takes exactly 1 argument (2 given)
如何在类中使用 lambda 作为方法？
使用/访问 lambda 类变量的可能性很小。其中三个是：
class BaseClass(object):
successify = lambda x: "<Success>%s</Success>" % x
errorify = lambda x: "<Error>%s</Error>" % x
def try1(self):
print(self.__class__.successify("try1"))
def try2(self):
print(self.__class__.successify("try2"))
# or
class BaseClass(object):
successify = lambda x: "<Success>%s</Success>" % x
errorify = lambda x: "<Error>%s</Error>" % x
def try1(self):
print(BaseClass.successify("try1"))
def try2(self):
print(BaseClass.successify("try2"))
# or Please not changes to lambda definitions below
class BaseClass(object):
successify = lambda self,x: "<Success>%s</Success>" % x
errorify = lambda self,x: "<Error>%s</Error>" % x
def try1(self):
print(self.successify("try1"))
def try2(self):
print(self.successify("try2"))
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