我正在尝试将 Expect 脚本实现到 bash 脚本中。请耐心等待，因为我对 bash/expect 还很陌生。
这是按预期工作的期望脚本：
log_user 0
file delete foo.txt
set fh [open foo.txt a]
set servers {xxx@server1 xxx@server2}
foreach s $servers {
spawn ssh $s
expect "password: "
send "PASSWORD\r"
expect "$ "
send "grep "something" /some/log/file.log"
expect "$ " { puts $fh "$expect_out(buffer)"}
send "exit\r"
}
close $fh
现在，我希望将此 Expect 脚本包含在 bash 脚本中，但它没有按预期工作。
这是我到目前为止所拥有的：
#!/bin/bash
XYZ=$(expect -c "
file delete foo.txt
set fh [open foo.txt a]
set servers {xxx@server1 xxx@server2}
foreach s $servers {
spawn ssh $s
expect "password: "
send "PASSWORD\r"
expect "$ "
send "grep "something" /some/log/file.log"
expect "$ " { puts $fh "$expect_out(buffer)"}
send "exit\r"
}
close $fh
")
echo "$XYZ"
我收到的错误是：
command substitution: line 42: syntax error near unexpected token `('
command substitution: line 42: `expect "$ " { puts $fh "$expect_out(buffer)"}'
我愿意接受任何其他方式来实现这一点！ :)
您可以使用/usr/bin/expect -c执行expect命令：
#!/bin/bash
/usr/bin/expect -c '
file delete foo.txt
set fh [open foo.txt a]
set servers {xxx@server1 xxx@server2}
foreach s $servers {
spawn ssh $s
expect "password: "
send "PASSWORD\r"
expect "$ "
send "grep "something" /some/log/file.log"
expect "$ " { puts $fh "$expect_out(buffer)"}
send "exit\r"
}
close $fh
'
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