如何在plotly中绘制饼图？

如何在“fig”中绘制“pie1”子图，使其位于“第一个”位置。我就是这样做的，但没有成功

    import pandas as pd
    import numpy as np
    import seaborn as sns
    import plotly.offline as pyp
    import plotly.graph_objs as go
    from plotly import tools
    import plotly.plotly as py
    from plotly.offline import iplot,init_notebook_mode
    from IPython.core.display import HTML
    import plotly.io

    df1=pd.read_excel('file.xlsx',sheet_name='sheet1',index=False)
    con_pivot=pd.pivot_table(con,index='Category',values=('Payment'),aggfunc='sum',margins=True,margins_name='Total')

    fig = tools.make_subplots(rows=2, cols=2, subplot_titles=('The first','3','2','4'))

    pie1=go.Pie(labels=con_pivot.index,values=con_pivot.values)
    fig.append_trace(pie1,1,1)
    pyo.plot(fig)

任何帮助将不胜感激。 谢谢

使用并排饼图实现的方法make_subplots来自plotly 的函数如下（非常感谢@Oysiyl 提供的输入数据）：

from plotly.subplots import make_subplots
import plotly.graph_objects as go
from plotly.offline import plot


fig = make_subplots(rows=1, cols=2, specs=[[{"type": "pie"}, {"type": "pie"}]])


fig.add_trace(go.Pie(
     values=[16, 15, 12, 6, 5, 4, 42],
     labels=["US", "China", "European Union", "Russian Federation",
             "Brazil", "India", "Rest of World"
             ],
     domain=dict(x=[0, 0.5]),
     name="GHG Emissions"), 
     row=1, col=1)

fig.add_trace(go.Pie(
     values=[27, 11, 25, 8, 1, 3, 25],
     labels=["US", "China", "European Union", "Russian Federation",
             "Brazil", "India", "Rest of World"
             ],
     domain=dict(x=[0.5, 1.0]),
     name="CO2 Emissions"),
    row=1, col=2)

plot(fig)