我有一个表格,每个单元格都有一个弹出窗口,如下例所示:
对弹出窗口的调用:
<td ng-repeat="i in c.installments" ng-class="{ 'first' : i.first, 'last' : i.last, 'advance' : i.advance.value > 0, 'edited' : i.edited, 'final-installment' : i.last }" popover-trigger="{{ popoverFilter(i) }}" popover-placement="top" popover-title="{{i.id == 0 ? 'Advance' : 'Installment ' + i.id}}" popover-append-to-body="true" popover-template="popoverTemplate(i)" ng-init="payment= i; newpayment= i.amount.rounded_value" >
弹出框模板:
<script type="text/ng-template" id="editPopoverTemplate.html">
<form name="editPayment">
<h2>{{payment.amount.value|currency:undefined:cents}}</h2>
<div class="form-group" ng-class="{ 'has-error' : editPayment.newpayment.$invalid }">
<label>New value:</label>
<input type="number" name="newpayment" ng-model="newpayment" class="form-control no-spinner" step="1" min="10" required>
<span ng-messages="editPayment.newpayment.$error" class="help-block" role="alert">
<span ng-message="required">The value is mandatory</span>
<span ng-message="min">The value is too low</span>
<span ng-message="max">The value is too hight</span>
</span>
</div>
<div class="btn-group btn-group-justified" role="group">
<div class="btn-group" role="group">
<button class="btn" type="button">Cancel</button>
</div>
<div class="btn-group" role="group">
<button class="btn btn-primary" type="button" ng-disabled="editPayment.$invalid">Save</button>
</div>
</div>
</form>
</script>
plunker 的工作示例 http://plnkr.co/edit/ArIDkkXs9Ev6ROBLSvDd?p=preview
我需要通过弹出窗口内的“取消”按钮关闭弹出窗口。
这是可能的?我需要扩展 Angular UI Bootstrap 库才能做到这一点?
任何帮助表示赞赏。
当用户单击弹出窗口内部或弹出窗口外部时,链接答案中建议的解决方案会关闭弹出窗口,但我需要通过弹出窗口内的“关闭”按钮将其关闭。
使用新的正确解决方案popover-is-open
正如下面@icfantv 所提到的,属性允许使用控制器作用域。我在中放置了一个实例Codepen http://codepen.io/dmvianna/pen/OyNNJx,它是这样的:
app = angular.module('ui.bootstrap.demo', ['ui.bootstrap']);
app.controller(
'myPopoverCtrl', ['$scope',
function($scope) {
// query popover
$scope.myPopover = {
isOpen: false,
templateUrl: 'myPopoverTemplate.html',
open: function open() {
$scope.myPopover.isOpen = true;
$scope.myPopover.data = 'Hello!';
},
close: function close() {
$scope.myPopover.isOpen = false;
}
};
}
]);
<head>
<script src="//ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<script src="//ajax.googleapis.com/ajax/libs/angularjs/1.3.14/angular.min.js"></script>
<script src="//maxcdn.bootstrapcdn.com/bootstrap/3.3.5/js/bootstrap.min.js"></script>
<script src="//cdnjs.cloudflare.com/ajax/libs/angular-ui-bootstrap/0.13.4/ui-bootstrap-tpls.min.js">
</script>
<link rel="stylesheet" href="//maxcdn.bootstrapcdn.com/bootstrap/3.3.5/css/bootstrap.min.css">
</head>
<body
ng-app="ui.bootstrap.demo"
class="container">
<button
class="btn btn-danger"
ng-controller="myPopoverCtrl"
popover-template="myPopover.templateUrl"
popover-title="This is a popover"
popover-placement="bottom"
popover-is-open="myPopover.isOpen"
ng-click="myPopover.open()">Click me!</button>
<script type="text/ng-template"
id="myPopoverTemplate.html">
<h2 ng-bind="myPopover.data" />
<button class="btn btn-success"
ng-click="myPopover.close()">Close me!</button>
</script>
</body>
原答案:
我花了两天时间解决这个问题,终于想出了一个足够简单的技巧。这在我的控制器上进行:
$scope.close = function(e) {
el = angular.element(e.target).closest("td"); // `td` is the parent of my clickable
// element, in this case a `span`
$timeout(function() { // need $timeout so we don't conflict with the digest loop
el.children(":first").trigger('close'); // couldn't select the `span` element directly
});
},
现在我们设置了close在提供者上触发:
app.config(['$tooltipProvider', function($tooltipProvider){
$tooltipProvider.setTriggers({
'click': 'close', // Clicks now only open the tooltip, 'close' events close it.
});
}]);
在我的自定义弹出窗口 HTML 模板上:
<button type="button"
class="btn btn-sm btn-success pull-right"
ng-click="close($event)">Close</button>
瞧!我现在可以通过按钮关闭弹出窗口!
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