嗨,我对 Alamofire 和 json 还很陌生。我只是想问如何处理成功响应的错误。下面是 api 对 post 请求的响应。
{
data = {
"cabinet_id" = 3289146811;
"created_at" = "2018-04-11T04:53:43.288023001Z";
"user_id" = 123abc;
};
}
但有时由于服务器错误我得到如下响应
{
error = {
"http_status_code" = 400;
message = "Unable to proceed";
type = "rent_request_failed";
};
}
这就是我所做的
let url = "myurl"
let parameters = ["user_id": ""\(self.idPassed)"",
"cabinet_id": "\(self.stringPassed)"]
Alamofire.request(url, method: .post, parameters: parameters, encoding: URLEncoding.default).responseJSON { response in
if (response.result.isSuccess){
if let value = response.result.value {
//now success or failed always navigate to here
Helper.helper.switchToNavigationViewController(Navigation: "hundredpercent")
print(value)
}
//do your json stuff
} else if (response.result.isFailure) {
//Manager your error
switch (response.error!._code){
case NSURLErrorTimedOut:
//Manager your time out error
break
case NSURLErrorNotConnectedToInternet:
//Manager your not connected to internet error
break
default:
let alertt = UIAlertController(title: "Server Error!", message: "Please try again", preferredStyle: .alert)
alertt.addAction(UIAlertAction(title: "OK", style: UIAlertActionStyle.default, handler: {(action:UIAlertAction!) in
//need navigate here if error
Helper.helper.switchToNavigationViewController(Navigation: "qrcodescan")
}))
self.present(alertt, animated: true)
}
}
}
通过添加在调用 API 时验证响应状态代码validate(statusCode: 200..<299)
根据阿拉莫菲尔的要求。
如果您的http状态代码位于区间内,它将验证成功200-299
否则进入失败案例。
// Call response handler method of alamofire
Alamofire.request(url, method: .post, parameters: parameters, encoding: URLEncoding.default).validate(statusCode: 200..<299).responseJSON(completionHandler: { response in
switch response.result {
case .success(let data):
Logs.DLog(object: "\n Success: \(response)")
// Do your code here...
case .failure(let error):
Logs.DLog(object: "\n Failure: \(error.localizedDescription)")
// Do your code here...
}
})
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