如何根据 pandas 列注释散点图中的点

Wanted 'Age'作为 x 轴，'Pos'作为 y 轴，标签为'Player'名字。但由于某种原因，无法对点进行标记。

Code:

import numpy as np
import matplotlib.pyplot as plt
import pandas as pd
import adjustText as at



data = pd.read_excel("path to  the file")
fig, ax = plt.subplots()
fig.set_size_inches(7,3)

df = pd.DataFrame(data, columns = ['Player', 'Pos', 'Age'])

df.plot.scatter(x='Age',
                y='Pos',
                c='DarkBlue', xticks=([15,20,25,30,35,40]))

y = df.Player
texts = []
for i, txt in enumerate(y):
    plt.text()
at.adjust_text(texts, arrowprops=dict(arrowstyle="simple, head_width=0.25, tail_width=0.05", color='black', lw=0.5, alpha=0.5))

plt.show()

数据摘要：

df.head()

             Player Pos  Age
0  Thibaut Courtois  GK   28
1     Karim Benzema  FW   32
2      Sergio Ramos  DF   34
3    Raphael Varane  DF   27
4       Luka Modric  MF   35

Error :

ConversionError：无法将值转换为轴单位：“GK”

This is the plot so far; not able to label these points:

EDIT: This is what I wanted but of all points:

另外，任何人都可以帮我重新排序 yaxis 上的标签吗？ 就像，我想要 FW，MF，DF，GK 作为我的顺序，但情节是在 MF，DF，FW，GK 中。

Thanks.

描述了类似的解决方案here https://stackoverflow.com/questions/14432557/matplotlib-scatter-plot-with-different-text-at-each-data-point。本质上，您想要注释散点图中的点。

我已经剥离了你的代码。请注意，您需要使用以下命令绘制数据matplotlib（并且不与pandas): df = pd.DataFrame(data, columns = ['Player', 'Pos', 'Age'])。通过这种方式，您可以使用annotation()-method.

import matplotlib.pyplot as plt
import pandas as pd

# build data
data = [
['Thibaut Courtois', 'GK', 28],
['Karim Benzema', 'FW', 32],
['Sergio Ramos','DF', 34],
['Raphael Varane', 'DF', 27],
['Luka Modric', 'MF', 35],
]
# create pandas DataFrame
df = pd.DataFrame(data, columns = ['Player', 'Pos', 'Age'])


# open figure + axis
fig, ax = plt.subplots()
# plot
ax.scatter(x=df['Age'],y=df['Pos'],c='DarkBlue')
# set labels
ax.set_xlabel('Age')
ax.set_ylabel('Pos')

# annotate points in axis
for idx, row in df.iterrows():
    ax.annotate(row['Player'], (row['Age'], row['Pos']) )
# force matplotlib to draw the graph
plt.show()

这是您将得到的输出：