这是我试图通过 sqlalchemy 生成的查询
SELECT "order".id AS "id",
"order".created_at AS "created_at",
"order".updated_at AS "updated_at",
CASE
WHEN box.order_id IS NULL THEN "special"
ELSE "regular" AS "type"
FROM "order" LEFT OUTER JOIN box ON "order".id = box.order_id
按照sqlalchemy的文档,我尝试使用hybrid_property来实现这一点。这是我到目前为止所得到的,但我没有得到正确的说法。它没有正确生成 case 语句。
from sqlalchemy import (Integer, String, DateTime, ForeignKey, select, Column, create_engine)
from sqlalchemy.orm import relationship, sessionmaker
from sqlalchemy.ext.declarative import declarative_base
from sqlalchemy.ext.hybrid import hybrid_property
Base = declarative_base()
class Order(Base):
__tablename__ = 'order'
id = Column(Integer, primary_key=True)
created_at = Column(DateTime)
updated_at = Column(DateTime)
order_type = relationship("Box", backref='order')
@hybrid_property
def type(self):
if not self.order_type:
return 'regular'
else:
return 'special'
class Box(Base):
__tablename__ = 'box'
id = Column(Integer, primary_key=True)
monthly_id = Column(Integer)
order_id = Column(Integer, ForeignKey('order.id'))
stmt = select([Order.id, Order.created_at, Order.updated_at, Order.type]).\
select_from(Order.__table__.outerjoin(Box.__table__))
print(str(stmt))