我试图从用户表中提取与 users_groups 数据透视表中某个组匹配的所有用户。顺便说一句,我使用的是来自 Cartalyst 的 Sentry 2。
这可以让所有用户的名字和姓氏连接起来。
User::select(DB::raw('CONCAT(last_name, ", ", first_name) AS full_name'), 'id')
->where('activated', '=', '1')
->orderBy('last_name')
->lists('full_name', 'id');
当我尝试更改它以过滤不属于某个组的用户时,我收到语法错误。
User::select(DB::raw('SELECT CONCAT(user.last_name, ", ", user.first_name) AS user.full_name'), 'user.id', 'users_groups.group_id', 'users_groups.user_id')
->join('users_groups', 'user.id', '=', 'users_groups.user_id')
->where('user.activated', '=', '1')
->where('users_groups.group_id', '=', $group)
->orderBy('user.last_name')
->lists('user.full_name', 'user.id');
任何朝着正确方向的推动将不胜感激。
编辑:语法错误
SQLSTATE[42000]: Syntax error or access violation: 1064 You have an error in
your SQL syntax; check the manual that corresponds to your MySQL server
version for the right syntax to use near 'SELECT CONCAT(user.last_name, ", ",
user.first_name) AS user.full_name, `user`.`' at line 1 (SQL: select SELECT
CONCAT(user.last_name, ", ", user.first_name) AS user.full_name, `user`.`id`,
`users_groups`.`group_id`, `users_groups`.`user_id` from `users` inner join
`users_groups` on `user`.`id` = `users_groups`.`user_id` where
`users`.`deleted_at` is null and `user`.`activated` = 1 and
`users_groups`.`group_id` = 9 order by `user`.`last_name` asc)