如何将Set转换为Array？

本文翻译自：How to convert Set to Array?

Set seems like a nice way to create Arrays with guaranteed unique elements, but it does not expose any good way to get properties, except for generator [Set].values, which is called in an awkward way of mySet.values.next() . Set似乎是一种创建具有保证唯一元素的Arrays的好方法，但它没有暴露任何获取属性的好方法，除了生成器[Set] .values，它以mySet.values.next()的笨拙方式mySet.values.next() 。

This would have been ok, if you could call map and similar functions on Sets. 如果您可以在集合上调用map和类似函数，那就没问题了。 But you cannot do that, as well. 但你也不能这样做。

I've tried Array.from , but seems to be converting only array-like (NodeList and TypedArrays ?) objects to Array. 我尝试过Array.from ，但似乎只是将类似数组（NodeList和TypedArrays？）的对象转换为Array。 Another try: Object.keys does not work for Sets, and Set.prototype does not have similar static method. 另一个尝试： Object.keys不适用于Sets，而Set.prototype没有类似的静态方法。

So, the question: Is there any convenient inbuilt method for creating an Array with values of a given Set ? 所以，问题是 ： 是否有任何方便的内置方法来创建具有给定Set值的数组？ (Order of element does not really matter). （元素的顺序并不重要）。

if no such option exists, then maybe there is a nice idiomatic one-liner for doing that ? 如果没有这样的选择，那么也许有一个很好的惯用的单行代码呢？ like, using for...of , or similar ? 比如， for...of或类似的？

#1楼

参考：https://stackoom.com/question/1MD4u/如何将Set转换为Array

#2楼

if no such option exists, then maybe there is a nice idiomatic one-liner for doing that ? 如果没有这样的选择，那么也许有一个很好的惯用的单行代码呢？ like, using for...of, or similar ? 比如，用于...或类似的？

Indeed, there are several ways to convert a Set to an Array : 实际上，有几种方法可以将Set转换为数组 ：

using Array.from 使用Array.from

let array = Array.from(mySet);

Simply spreading the Set out in an array 简单地spreading Set spreading为数组

let array = [...mySet];

The old fashion way, iterating and pushing to a new array (Sets do have forEach ) 旧的时尚方式，迭代并推送到一个新的数组（集合有forEach ）

let array = [];
mySet.forEach(v => array.push(v));

Previously, using the non-standard, and now deprecated array comprehension syntax: 以前，使用非标准，现在不推荐使用的数组解析语法：

let array = [v for (v of mySet)];

#3楼

via https://speakerdeck.com/anguscroll/es6-uncensored by Angus Croll 通过https://speakerdeck.com/anguscroll/es6-由Angus Croll提供

It turns out, we can use spread operator: 事实证明，我们可以使用spread运算符：

var myArr = [...mySet];

Or, alternatively, use Array.from : 或者，使用Array.from ：

var myArr = Array.from(mySet);

#4楼

Assuming you are just using Set temporarily to get unique values in an array and then converting back to an Array, try using this: 假设您只是暂时使用Set来获取数组中的唯一值，然后转换回Array，请尝试使用：

_.uniq([])

This relies on using underscore or lo-dash . 这依赖于使用下划线或lo-dash 。

#5楼

Perhaps to late to the party, but you could just do the following: 也许到了晚会，但你可以做到以下几点：

const set = new Set(['a', 'b']);
const values = set.values();
const array = Array.from(values);

This should work without problems in browsers that have support for ES6 or if you have a shim that correctly polyfills the above functionality. 这应该在支持ES6的浏览器中没有问题，或者如果你有一个正确填充上述功能的垫片。

Edit : Today you can just use what @c69 suggests: 编辑 ：今天你可以使用@ c69建议的内容：

const set = new Set(['a', 'b']);
const array = [...set]; // or Array.from(set)

#6楼

使用spread运算符可以获得所需的结果

var arrayFromSet = [...set];