对于第一帧的第一个包开始为PS头+系统头+节目映射流
1) Pack start code：包起始码字段，值为0x000001BA的位串，用来标志一个包的开始。
2) System clock reference base，system clock reference extenstion：系统时钟参考字段。
3) Pack stuffing length ：包填充长度字段，3 位整数，规定该字段后填充字节的个数
80 60 53 1f 00 94 89 00 00 0000 00 00 00 01 ba €`S..??........?
7e ff 3e fb 44 01 00 5f 6b f8 00 00 01 e0 14 53 ~.>?D.._k?...?.S
80 80 05 2f bf cf bed1 1c 42 56 7b 13 58 0a 1e €€./????.BV{.X..
08 b1 4f 33 69 35 0453 6d 33 a8 04 15 58 d9 21 .?O3i5.Sm3?..X?!
9741 b9 f1 75 3d 94 2b 1f bc 0b b2 b4 97 bf 93 ?A??u=?+.?.?????
前12位是RTP Header，这里不再赘述；
000001ba是包头起始码；
接下来的9位包括了SCR，SCRE，MUXRate，具体看图7
最后一位是保留位（0xf8），定义了是否有扩展，二进制如下
1111 1000
前5位跳过，后3位指示了扩展长度，这里是0.
000001ba5cd2cf388401028f63fe ffff00575ece PS头
000001bb00 12 //长度
8147b104e17fe0e080c0c008bde080bfe080 系统头
000001bc 004e//长度
eeff 0024(stream info len)
400e484b01001195a89df27700ffffff4112484b000102030405060708090a0b0c0d0e0f
0020(stream map len) 1b(stream type) e0(stream id) // stream id & stream type can detemine the codec
0x1b && e0 ----> h264
0x24 && e0 ----> H265
001c420e030810ea07800438111f00001c202a0a7fff000007081ffef0874b920c23 节目映射头
000001e0 002a//长度
8c800a 2734b3ce21(TS) fffffffffc //OPTIONAL PES header
00000001674d00299a6603c0113f2cd404040500000303e80000c35004 // PES 头
000001e0 000e
8c0003 fffffc // PES OPTIONAL header
0000000168ee3c80 // PES 头
000001e0 97de
8c0002 fff8
00000001(H264 startcode) 65(NALU type) 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
startcode followed with:
其中0x67的二进制码为：
0110 0111
4-8为00111，转为十进制7，参考第二幅图：7对应序列参数集SPS
其中0x68的二进制码为：
0110 1000
4-8为01000，转为十进制8，参考第二幅图：8对应图像参数集PPS
其中0x65的二进制码为：
0110 0101
4-8为00101，转为十进制5，参考第二幅图：5对应IDR图像中的片(I帧)
其中0x41的二进制码为：
0100 0001
4-8为00001，转为十进制1，参考第二幅图：根据上图可知道这段码流是【不分区、非IDR图像的片】，在baseline的档次中就是P帧，因为baseline没有B帧。
所以判断是否为I帧的算法为： （NALU类型 & 0001 1111） = 5 即 NALU类型 & 31 = 5
比如0x65 & 31 = 5
PTS DTS标志字段 PTS_DTS_flags
2位字段。当值为'10'时，PTS字段应出现在PES分组标题中；当值为'11'时，PTS字段和DTS字段都应出现在PES分组标题中；当值为'00'时，PTS字段和DTS字段都不出现在PES分组标题中。值'01'是不允许的。
中间的某一些帧
000001ba5cd2d4198401028f63fe ffff00575ed0 //PS header
000001e0 0aa2
//1374+
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
//1348 +1374 == aa2
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