【牛客SQL】SQL23 对所有员工的薪水按照salary降序进行1-N的排名

题目描述

描述
有一个薪水表salaries简况如下:

对所有员工的薪水按照salary降序进行1-N的排名，要求相同salary并列且按照emp_no升序排列：

示例1
输入：
drop table if exists  `salaries` ; 
CREATE TABLE `salaries` (
`emp_no` int(11) NOT NULL,
`salary` int(11) NOT NULL,
`from_date` date NOT NULL,
`to_date` date NOT NULL,
PRIMARY KEY (`emp_no`,`from_date`));
INSERT INTO salaries VALUES(10001,88958,'2002-06-22','9999-01-01');
INSERT INTO salaries VALUES(10002,72527,'2001-08-02','9999-01-01');
INSERT INTO salaries VALUES(10003,43311,'2001-12-01','9999-01-01');
INSERT INTO salaries VALUES(10004,72527,'2001-12-01','9999-01-01');
复制
输出：
10001|88958|1
10002|72527|2
10004|72527|2
10003|43311|3

题解

做题的做法

运行时间：14ms
超过73.52% 用Sqlite提交的代码
占用内存：3560KB
超过17.57%用Sqlite提交的代码

SELECT s1.emp_no, s1.salary, (
    SELECT COUNT(DISTINCT s2.salary) + 1
    FROM salaries s2
    WHERE s2.salary > s1.salary
) AS t_rank
FROM salaries s1
ORDER BY salary DESC
;

MySQL实际还可以

SELECT emp_no, salary,
DENSE_RANK() OVER(ORDER BY salary DESC) AS t_rank
FROM salaries
ORDER BY t_rank, emp_no;