Python实现十进制小数转IEEE754单精度浮点数转换

def ConvertFixedIntegerToComplement(fixedInterger) :#浮点数整数部分转换成补码(整数全部为正)
    return bin(fixedInterger)[2:]

def ConvertFixedDecimalToComplement(fixedDecimal) :#浮点数小数部分转换成补码
    fixedpoint = int(fixedDecimal) / (10.0**len(fixedDecimal))
    s = ''
    while fixedDecimal != 1.0 and len(s) < 23 :
        fixedpoint = fixedpoint * 2.0
        s += str(fixedpoint)[0]
        fixedpoint = fixedpoint if str(fixedpoint)[0] == '0' else fixedpoint - 1.0
    return s

def ConvertToExponentMarker(number) : #阶码生成
    return bin(number + 127)[2:].zfill(8)


def ConvertToFloat(floatingPoint) :#转换成IEEE754标准的数
    floatingPointString = str(floatingPoint)
    if floatingPointString.find('-') != -1 :#判断符号位
        sign = '1'
        floatingPointString = floatingPointString[1:]
    else :
        sign = '0'
    l = floatingPointString.split('.')#将整数和小数分离
    front = ConvertFixedIntegerToComplement(int(l[0]))#返回整数补码
    rear  = ConvertFixedDecimalToComplement(l[1])#返回小数补码
    floatingPointString = front + '.' + rear #整合
    relativePos =   floatingPointString.find('.') - floatingPointString.find('1')#获得字符1的开始位置
    if relativePos > 0 :#若小数点在第一个1之后
        exponet = ConvertToExponentMarker(relativePos-1)#获得阶码
        mantissa =  floatingPointString[floatingPointString.find('1')+1 : floatingPointString.find('.')]  + floatingPointString[floatingPointString.find('.') + 1 :] # 获得尾数
    else :
        exponet = ConvertToExponentMarker(relativePos)#获得阶码
        mantissa = floatingPointString[floatingPointString.find('1') + 1: ]  # 获得尾数
    mantissa =  mantissa[:23] + '0' * (23 - len(mantissa))
    floatingPointString = '0b' + sign + exponet + mantissa
    print(floatingPointString)
    return hex( int( floatingPointString , 2 ) )

print(ConvertToFloat(20.59375))