我正在尝试创建一个程序,使用 3 个八进制数(例如 5、2、6 或 5、2、6)的命令行获取用户输入,并将它们转换为 3 组 3 位二进制数,例如 101 010 110,并打印出相应的 CHMOD 权限,例如 r-x -w- rw-。
我在将这些数字与子字符串拼接成 3 个单独的数字 5 2 和 6 时遇到了很多麻烦。
我还需要该程序将一组二进制数字转换为 3 位数字和权限。并从权限转换为数字和二进制。
这是我到目前为止所拥有的:
import java.util.Scanner;
class Test {
public static void main(String cheese[]){
Scanner scan = new Scanner(System.in);
String line1 = scan.nextLine();
//String line2 = scan.nextLine();
//String line3 = scan.nextLine();
//String line4 = scan.nextLine();
//String line5 = scan.nextLine();
System.out.println(line12(line1));
}
public static String line12(String line){
String ownerPermissions = "";
String groupPermissions = "";
String otherPermissions = "";
int comma = 0;
int lineLength = line.length();
if (line.indexOf(" ") != -1){
comma = line.indexOf(",");
}else{
comma = 1;
}
String firstNumber = line.substring(0, 1);
line = line.substring(comma + 1, lineLength);
int comma2 = line.indexOf(",");
String secondNumber = line.substring(comma + 1, comma2);
String thirdNumber = line.substring(lineLength);
int firstInt= Integer.parseInt(firstNumber);
int secondInt = Integer.parseInt(secondNumber);
int thirdInt = Integer.parseInt(thirdNumber);
String firstBinary = Integer.toBinaryString(firstInt);
String secondBinary = Integer.toBinaryString(secondInt);
String thirdBinary = Integer.toBinaryString(thirdInt);
switch(firstInt){
case 0:
ownerPermissions = "---";
break;
case 1:
ownerPermissions = "--x";
break;
case 2:
ownerPermissions = "-w-";
break;
case 3:
ownerPermissions = "-wx";
break;
case 4:
ownerPermissions = "r--";
break;
case 5:
ownerPermissions = "r-x";
break;
case 6:
ownerPermissions = "rw-";
break;
case 7:
ownerPermissions = "rwx";
break;
}
switch(secondInt){
case 0:
groupPermissions = "---";
break;
case 1:
groupPermissions = "--x";
break;
case 2:
groupPermissions = "-w-";
break;
case 3:
groupPermissions = "-wx";
break;
case 4:
groupPermissions = "r--";
break;
case 5:
groupPermissions = "r-x";
break;
case 6:
groupPermissions = "rw-";
break;
case 7:
groupPermissions = "rwx";
break;
}
switch(thirdInt){
case 0:
otherPermissions = "---";
break;
case 1:
otherPermissions = "--x";
break;
case 2:
otherPermissions = "-w-";
break;
case 3:
otherPermissions = "-wx";
break;
case 4:
otherPermissions = "r--";
break;
case 5:
otherPermissions = "r-x";
break;
case 6:
otherPermissions = "rw-";
break;
case 7:
otherPermissions = "rwx";
break;
}
String output = firstBinary + " " + secondBinary + " " + thirdBinary + " and " + ownerPermissions + " " + groupPermissions + " " + otherPermissions;
return output;
}
}
如果你让你的代码变得更简单,你会发现它更容易。我建议类似的东西
public static void main(String[] args) {
System.out.println(line12("5, 2, 6"));
}
public static String line12(String line) {
String[] nums = line.trim().split(" *, *");
StringBuilder sb = new StringBuilder();
for (String s : nums) {
if (sb.length() > 0) sb.append(" ");
int num = Integer.parseInt(s);
sb.append((num & 4) == 0 ? '-' : 'r');
sb.append((num & 2) == 0 ? '-' : 'w');
sb.append((num & 1) == 0 ? '-' : 'x');
}
return sb.toString();
}
prints
r-x -w- rw-
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