使用另一个文件中的行范围替换单独文件中字符串中出现的每 2 个 n

我有三个文件：

0.txt e 0-1.txt具有以下相同内容：

"#sun\t",
"car_snif = house.group_tree(home_cool)\t",
"machine(shoes_shirt.shop)\t",
"car_snif = house.group_tree(home_cool)\t",
"machine(shoes_shirt.shop)\t",
"car_snif = house.group_tree(home_cool)\t",
"machine(shoes_shirt.shop)\t",
"car_snif = house.group_tree(home_cool)\t",
"machine(shoes_shirt.shop)\t",
"#sun\t",
"car_snif = house.group_tree(home_cool)\t",
"machine(shoes_shirt.shop)\t",
"car_snif = house.group_tree(home_cool)\t",
"machine(shoes_shirt.shop)\t",
"car_snif = house.group_tree(home_cool)\t",
"machine(shoes_shirt.shop)\t",
"car_snif = house.group_tree(home_cool)\t",

和源文件1.txt below:

(food, apple,)(bag, tortoise,)
(sky, cat,)(sun, sea,)
(car, shape)(milk, market,)
(man, shirt)(hair, life)
(dog, big)(bal, pink)

For 0.txt我想更换每一个2 nth发生于home_cool by 1 nth 1.txt行，但只使用最多第二行1.txt (then sed -n '1,2p'），这样我的2.txt输出如下：

"#sun\t",
"car_snif = house.group_tree((food, apple,)(bag, tortoise,))\t",
"machine(shoes_shirt.shop)\t",
"car_snif = house.group_tree((food, apple,)(bag, tortoise,))\t",
"machine(shoes_shirt.shop)\t",
"car_snif = house.group_tree((sky, cat,)(sun, sea,))\t",
"machine(shoes_shirt.shop)\t",
"car_snif = house.group_tree((sky, cat,)(sun, sea,))\t",
"machine(shoes_shirt.shop)\t",
"#sun\t",
"car_snif = house.group_tree((food, apple,)(bag, tortoise,))\t",
"machine(shoes_shirt.shop)\t",
"car_snif = house.group_tree((food, apple,)(bag, tortoise,))\t",
"machine(shoes_shirt.shop)\t",
"car_snif = house.group_tree((sky, cat,)(sun, sea,))\t",
"machine(shoes_shirt.shop)\t",
"car_snif = house.group_tree((sky, cat,)(sun, sea,))\t",

当完成该过程时2.txt,我想全部替换掉2 nth发生于home_cool at 0-1.txt by 1 nth 1.txt使用第三行的行1.txt从此（然后sed -n '3,5p'），这样我的3.txt输出如下：

"#sun\t",
"car_snif = house.group_tree((car, shape)(milk, market,))\t",
"machine(shoes_shirt.shop)\t",
"car_snif = house.group_tree((car, shape)(milk, market,))\t",
"machine(shoes_shirt.shop)\t",
"car_snif = house.group_tree((man, shirt)(hair, life))\t",
"machine(shoes_shirt.shop)\t",
"car_snif = house.group_tree((man, shirt)(hair, life))\t",
"machine(shoes_shirt.shop)\t",
"#sun\t",
"car_snif = house.group_tree((dog, big)(bal, pink))\t",
"machine(shoes_shirt.shop)\t",
"car_snif = house.group_tree((dog, big)(bal, pink))\t",
"machine(shoes_shirt.shop)\t",
"car_snif = house.group_tree((car, shape)(milk, market,))\t",
"machine(shoes_shirt.shop)\t",
"car_snif = house.group_tree((car, shape)(milk, market,))\t",

通过下面的行，我可以分为两个步骤来替换home_cool at 0.txt（第一步sed -n '1,2p'和第二步sed -n '3,5p'）。但我想保存第一步2.txt和第二步3.txt:

awk 'NR==FNR {a[NR]=$0; n=NR; next}/home_cool/ { gsub("home_cool", a[int((++i-1)%(n*2)/2)+1])}1' <(cat 1.txt | tee >(sed -n '1,2p') >(sed -n '3,5p')) 0.txt >> 2.txt

所以我真正想要的是类似的东西（下面的伪代码）：

awk 'NR==FNR {a[NR]=$0; n=NR; next}/home_cool/ { gsub("home_cool", a[int((++i-1)%(n*2)/2)+1])}1' <(cat 1.txt | tee >(sed -n '1,2p') >(sed -n '3,5p')) | "to sed -n '1,2p' make" 0.txt >> 2.txt | "to sed -n '3,5p' make" 0-1.txt >> 3.txt

我怎样才能通过维护命令行来做到这一点而不打破几个孤立的 awk 片段？

注意：也许问题的标题应该是“多个输入，相同的过程，不同的输出”

这有效：

awk \
'FNR==1 {++f}
f==1 {a[i++]=$0}
f==2 {if ($0~/home_cool/) {gsub(/home_cool/, a[int(j++/2)%2]) }; print > "2.txt"}
f==3 {if ($0~/home_cool/) {gsub(/home_cool/, a[int(k++/2)%3 + 2]) }; print > "3.txt"}' \
    1.txt 0.txt 0-1.txt

硬编码的替代方案"2.txt" and "3.txt"包括：

• 使用分配的变量-v outfile1=2.txt -v outfile2=2.txt
• 将它们替换为outfile，并使用这个参数列表：1.txt outfile=2.txt 0.txt outfile=3.txt 0-1.txt
• 将它们替换为ARGV[4] and ARGV[5]，添加行f==4 {exit}，并使用这个参数列表：1.txt 0.txt 0-1.txt 2.txt 3.txt

Caveats:

• 如果给定文件为空，则不会导致f增加并相应地打破事物。呆呆地，ENDFILE可以代替使用。看这个答案：如何获取 awk 脚本正在处理的文件号？ https://stackoverflow.com/questions/58015719/how-to-get-the-filenumber-that-is-being-processing-by-an-awk-script