多维数组的滑动最大窗口及其平均值

我有一个60 x 21 x 700矩阵，其中60 x 21代表一个pressure output x number of frames。我想找到2 x 2窗口生成每帧的最大平均压力并将其存储在新变量中以便可以绘制。例如，如果矩阵看起来像这样：

01 02 02 01 01
02 01 01 02 02
02 03 04 04 03
01 02 06 10 05
02 02 08 09 05

最大窗口及其平均值2 x 2窗口将是 -

06 10
08 09

= 8.25

到目前为止，在我寻找解决方案的过程中，我只能找到一种获得最大值的方法（例如10来自上面的矩阵），但确实无法弄清楚如何从没有固定索引可供参考的小区域中获取最大平均值。我对 MATLAB 相当陌生，因此，如果我错过了某些内容或者只是没有正确理解某些内容，我深表歉意。 任何帮助或指导将不胜感激。

二维数组：对于给定的二维数组输入，您可以使用2D convolution http://www.mathworks.com/help/matlab/ref/conv2.html -

%// Perform 2D convolution with a kernel of `2 x 2` size with all ones
conv2_out = conv2(A,ones(2,2),'same')

%// Find starting row-col indices of the window that has the maximum conv value
[~,idx] = max(conv2_out(:))
[R,C] = ind2sub(size(A),idx)

%// Get the window with max convolution value
max_window = A(R:R+1,C:C+1)

%// Get the average of the max window
out =  mean2(max_window)

代码的逐步运行示例 -

A =
     1     2     2     1     1
     2     1     1     2     2
     2     3     4     4     3
     1     2     6    10     5
     2     2     8     9     5
conv2_out =
     6     6     6     6     3
     8     9    11    11     5
     8    15    24    22     8
     7    18    33    29    10
     4    10    17    14     5
idx =
    14
R =
     4
C =
     3
max_window =
     6    10
     8     9
out =
         8.25

多维数组：对于多维数组的情况，您需要执行ND convolution http://www.mathworks.com/help/matlab/ref/convn.html -

%// Perform ND convolution with a kernel of 2 x 2 size with all ONES
conv_out = convn(A,ones(2,2),'same')

%// Get the average for all max windows in all frames/slices  
[~,idx] = max(reshape(conv_out,[],size(conv_out,3)),[],1)
max_avg_vals = conv_out([0:size(A,3)-1]*numel(A(:,:,1)) + idx)/4

%// If needed, get the max windows across all dim3 slices/frames
nrows = size(A,1)
start_idx = [0:size(A,3)-1]*numel(A(:,:,1)) + idx
all_idx = bsxfun(@plus,permute(start_idx(:),[3 2 1]),[0 nrows;1 nrows+1])
max_window = A(all_idx)

样本输入、输出 -

>> A
A(:,:,1) =
     4     1     9     9
     3     7     5     5
     9     6     1     6
     7     1     1     5
     4     2     2     1
A(:,:,2) =
     9     4     2     2
     3     6     4     5
     3     9     1     1
     6     6     8     8
     5     3     6     4
A(:,:,3) =
     5     5     7     7
     6     1     9     9
     7     7     5     4
     4     1     3     7
     1     9     3     1
>> max_window
max_window(:,:,1) =
     9     9
     5     5
max_window(:,:,2) =
     8     8
     6     4
max_window(:,:,3) =
     7     7
     9     9
>> max_avg_vals
max_avg_vals =
            7          6.5            8