我正在编写一个小脚本来捕获按键事件并轻松地在其上绑定函数。但我现在被困住了!
问题是,如果我初始化多个“事件处理程序”,它会覆盖第一次初始化的参数。
几千个字不比几行代码说得更多。所以,这就是我到目前为止所做的:
var keyCodes={a:65,b:66,c:67,d:68,e:69,f:70,g:71,h:72,i:73,j:74,k:75,l:76,m:77,n:78,o:79,p:80,q:81,r:82,s:83,t:84,u:85,v:86,w:87,x:88,y:89,z:90,"0":48,"1":49,"2":50,"3":51,"4":52,"5":53,"6":54,"7":55,"8":56,"9":57,f1:112,f2:113,f3:114,f4:115,f5:116,f6:117,f7:118,f8:119,f9:120,f10:121,f11:122,f12:123,shift:16,ctrl:17,control:17,alt:18,option:18,opt:18,cmd:224,command:224,fn:255,"function":255,backspace:8,"delete":8,enter:13,"return":13,left:37,up:38,right:39,down:40};
var keyCall = function(k, fn, c, e, k2, nk) {
this.onkeydown = function() {
nk = k.split(" ");
c = e ? e.which : event.keyCode;
if (nk.length > 1) {
if (keyCodes[nk[0]] === c) {
k2 = true;
}
if (keyCodes[nk[1]] === c && k2 === true) {
fn();
k2 = false;
}
} else if (keyCodes[nk[0]] === c) {
fn();
}
};
};
keyCall('ctrl a', function() { // overridden by `keyCall('shift a'`
alert('callback1');
});
keyCall('shift a', function() {
alert('callback2');
});
我已经将其优化为非常小的字节,如果您认为带注释的版本有用,那么就说出来吧!给有需要的大家,这里有fiddle http://jsfiddle.net/ARTsinn/HLUYt/
Update
pascalfree 已经修复了它!但现在另一个问题又来了……
“占位符”变量k2
检查是否按下了第一个键。但现在如果你按下然后松开ctrl
然后点击a
-key 该函数将被触发。有任何想法吗?