jquery数组分组依据

我有这样的数组

abcArr = [["A", 10], ["B", 20], ["A",30],["C",40]]

如何按 A、B、C 对值进行分组和求和...

$.each(abcArr , function() {
    if (this[0] == this[0]) { 
      this[1] + this[1] 
    }; // I know this will simple double [1] values :(
});

期望的结果应该是

[["A", 40], ["B", 20], ["C",30]]

这是一种简单的 javascript 方法，它收集映射中的唯一索引并对其进行总计，然后使用总计重新生成数组：

abcArr = [["A", 10], ["B", 20], ["A",30],["C",40]];

var items = {}, base, key;
for (var i = 0; i < abcArr.length; i++) {
    base = abcArr[i];
    key = base[0];
    // if not already present in the map, add a zeroed item in the map
    if (!items[key]) {
        items[key] = 0;
    }
    // add new item to the map entry
    items[key] += base[1];
}

// Now, generate new array
var outputArr = [], temp;
for (key in items) {
    // create array entry for the map value
    temp = [key, items[key]]
    // put array entry into the output array
    outputArr.push(temp);
}

// outputArr contains the result

工作演示：http://jsfiddle.net/jfriend00/vPMwu/ http://jsfiddle.net/jfriend00/vPMwu/

这是一种使用 jQuery 的方法.each:

abcArr = [["A", 10], ["B", 20], ["A",30],["C",40]];

var items = {}, base, key;
$.each(abcArr, function(index, val) {
    key = val[0];
    if (!items[key]) {
        items[key] = 0;
    }
    items[key] += val[1];
});

var outputArr = [];
$.each(items, function(key, val) {
    outputArr.push([key, val]);
});

// outputArr contains the result
document.body.innerHTML = JSON.stringify(outputArr);

工作演示：http://jsfiddle.net/jfriend00/Q8LLT/ http://jsfiddle.net/jfriend00/Q8LLT/