假设我有一个字符串,例如"x = 1, y = 'cat', z = NULL"
。我想获取代码创建的列表list(x = 1, z = 'cat', z = NULL)
。这是我的第一次尝试,我知道这是horrible:
parse_text <- function(x) parse(text = x)[[1]]
strsplit2 <- function(x, ...) strsplit(x, ...)[[1]]
trim_whitespace <- function (x) gsub("^\\s+|\\s+$", "", x)
# take 1
x <- "nk = 1, ncross = 1, pmethod = 'backward'"
x <- strsplit2(x, ",")
xs <- lapply(x, strsplit2, "=")
keys <- lapply(xs, function(x) trim_whitespace(x[1]))
vals <- lapply(xs, function(x) parse_text(x[2]))
setNames(vals, keys)
这就是我想象的更规范的方法:
# take 2
x <- "nk = 1, ncross = 1, pmethod = 'backward'"
x <- strsplit2(x, ",")
xs <- lapply(x, parse_text)
do.call(list, xs)
但这会丢失列表的名称。非常感谢任何帮助!干杯