在下面的 Swagger 定义中，我需要参数labelValue属于类型LabelValueObject，以便对其进行验证并正确反序列化。但是，我无法弄清楚语法！那怎么办呢？
swagger: "2.0"
paths:
/competition:
post:
parameters:
- name: labelValue
in: formData
type: array
items:
type: string ### this has to be a LabelValueObject ###
responses:
default:
description: Error
schema:
$ref: "#/definitions/AnyResponse"
definitions:
AnyResponse:
properties:
any:
type: string
LabelValueObject:
properties:
label:
type: string
value:
type: string
required:
- label
- value
将对象作为参数传递的唯一方法是将其放入主体中（in: body）然后在中定义这个对象schema（内联定义或对预定义对象的引用$ref）。这是一个完整的示例：
swagger: "2.0"
info:
title: A dummy title
version: 1.0.0
paths:
/competition:
post:
parameters:
- name: labelValue
in: body
schema:
$ref: '#/definitions/LabelValueObject'
responses:
default:
description: Error
schema:
$ref: "#/definitions/AnyResponse"
definitions:
AnyResponse:
properties:
any:
type: string
LabelValueObject:
properties:
label:
type: string
value:
type: string
required:
- label
- value
本文内容由网友自发贡献，版权归原作者所有，本站不承担相应法律责任。如您发现有涉嫌抄袭侵权的内容，请联系:hwhale#tublm.com(使用前将#替换为@)
