无法运行我的程序

尝试制作我的第一个程序“基本智力游戏”。

每次我尝试运行它时都没有显示任何内容，并且不知道出了什么问题。

希望您能给我一些帮助或建议。

顺便说一句，我在 Java 编程方面几乎是菜鸟，所以请轻松地评论:)

这是代码：

import java.util.*;
import java.util.Scanner.*;
import java.util.ArrayList.*;


 public class Main {
 public static void start() {

 int answer = (int) (Math.random() * 1000 + 1) ; 
 int tries = 0 ;
 int player ;
 String name = "name" ;
 String quit = "quit";
 String y = "yes";
 String n = "no";
 String guess = ("player") ;
 String another = ("Y") ;
 Scanner input = new Scanner (System.in);


    System.out.println( " Welcome to Guessing Game " ) ;
    System.out.print("Please enter a number between 1 and 1000 : ");
                    player = input.nextInt();
      long startTime = System.currentTimeMillis();
      int currentGuess = -1;



    while(another.equalsIgnoreCase("y")) {


      do
      {


               if (guess.equalsIgnoreCase(quit))
  {
   System.out.println("Leaving Us So Soon?");
   System.exit(0);
  }

               try    {
   currentGuess = Integer.parseInt(guess);
        } catch (NumberFormatException nfe) 
                        {
   System.out.println("Stupid Guess I Wont Count That.");
                        player = input.nextInt();
                        tries++;

   }


       if (currentGuess < answer )
          {
   System.out.println("too low");
   player = input.nextInt();
                        tries++;
  }


    else if(currentGuess  > answer )
  {
   System.out.println("too high");
   player = input.nextInt();
                        tries++;
  }
  //if the guess is invalid
  if (currentGuess < 0 || currentGuess > 1000)
  {
   System.out.println("Stupid Guess I Wont Count That.");
                        player = input.nextInt();
                        tries++;
  }
    else if (currentGuess == answer)
  {
   //stop stop watch
   long endTime = System.currentTimeMillis();
   //calculate game time
   long gameTime = endTime - startTime;
   System.out.println("You Rock Dude, Good Job!");

                        System.out.println("You guessed " + tries + " times in " + (int)(gameTime/1000) + " seconds.");
                        System.out.println("Please enter your name.");
            name = input.nextLine();
  }

        } while (player != answer);

      Scanner playGame = new Scanner(System.in);
   System.out.print("Want to go again?(y/n).....");
    another = playGame.nextLine();


    }
}

public static void main(String[] args) {

    }
}

你的主要方法是空的。

main 方法包含应用程序启动时将运行的代码。如果 main 方法为空，则运行应用程序时不会发生任何事情。