以下代码压缩一个数组，以便我可以看到某个值在数组中出现了多少次：
var str = "shopping-shopping-coupons-shopping-end";
var arr = str.split("-");
function compressArray(original) {
var compressed = [];
// make a copy of the input array
var copy = original.slice(0);
// first loop goes over every element
for (var i = 0; i < original.length; i++) {
var myCount = 0;
// loop over every element in the copy and see if it's the same
for (var w = 0; w < copy.length; w++) {
if (original[i] == copy[w]) {
// increase amount of times duplicate is found
myCount++;
// sets item to undefined
delete copy[w];
}
}
if (myCount > 0) {
var a = new Object();
a.value = original[i];
a.count = myCount;
compressed.push(a);
}
}
return compressed;
};
console.log(compressArray(arr));
但是，只有当元素连续重复时我才需要对其进行分组。因此，我想要的输出应该是：
[{"value": "shopping", "count": 2},
{"value": "coupons", "count": 1},
{"value": "shopping", "count": 1},
{"value": "end", "count": 1}]
我应该在哪里修改该函数，以便防止元素不连续时被计入键中？
您可以减少值并检查最后一个值是否等于实际值，然后增加最后一个计数或添加一个新对象。
function compressArray(original) {
return original.reduce((r, value) => {
var last = r[r.length - 1];
if (last && value === last.value) {
last.count++;
} else {
r.push({ value, count: 1 });
}
return r;
}, []);
};
var str = "shopping-shopping-coupons-shopping-end",
arr = str.split("-");
console.log(compressArray(arr));
.as-console-wrapper { max-height: 100% !important; top: 0; }
本文内容由网友自发贡献，版权归原作者所有，本站不承担相应法律责任。如您发现有涉嫌抄袭侵权的内容，请联系:hwhale#tublm.com(使用前将#替换为@)
