我是 hibernate 的新手，我希望它通过 JNDI 使用来自应用程序服务器的数据库连接。
奇怪的是，它在数据库中创建我的表，但不保存实体。看来，它并没有承诺。
有人在使用 hibernate 时遇到过类似的问题吗？
这是一个小测试 servlet：
public class WriteTest extends HttpServlet
{
@Override
public void doGet(HttpServletRequest request, HttpServletResponse response)
{
/*try
{
User user = new User("Hans", "Maulwurf", "[email protected] /cdn-cgi/l/email-protection");
InitialContext ctx = new InitialContext();
UserFacadeBean bean = (UserFacadeBean) ctx.lookup("ejb/UserFacadeBeanService");
bean.persist(user);
}
catch (NamingException e)
{
// TODO Auto-generated catch block
e.printStackTrace();
}*/
EntityManager em = JpaUtil.getEntityManagerFactory().createEntityManager();
//em.getTransaction().begin();
System.out.println("Begin transfer");
User user = new User("Hans", "Maulwurf", "[email protected] /cdn-cgi/l/email-protection");
Adress adress = new Adress("Deppenstraße 3","Deppingen");
//user.setAddress(adress);
System.out.println("Save User 'Hans Maulwurf'");
em.persist(user);
//em.persist(adress);
//em.getTransaction().commit();
em.close();
System.out.println("Everything went better than expected!");
}
}
这是小助手类：
public class JpaUtil
{
private static final EntityManagerFactory emf;
static
{
try
{
System.out.println("Initialize EntityManagerFactory...");
emf = Persistence.createEntityManagerFactory("testPU");
}
catch (Throwable ex)
{
System.err.println("Initial EntityManagerFactory creation failed." + ex);
throw new ExceptionInInitializerError(ex);
}
}
public static EntityManagerFactory getEntityManagerFactory()
{
return emf;
}
}
我的用户对象：
@Entity
@Table(name = "T_UserJpa")
public class User implements Serializable
{
@Id
@GeneratedValue(strategy = GenerationType.AUTO)
private Long id;
@Embedded
@AttributeOverrides(
{
@AttributeOverride(name = "street", column =
@Column(name = "user_street")),
@AttributeOverride(name = "city", column =
@Column(name = "user_city", length = 50))
})
private Adress adress;
private String firstname;
private String lastname;
private String email;
public User()
{
}
public User(String firstname, String lastname, String email)
{
this.firstname = firstname;
this.lastname = lastname;
this.email = email;
}
public Long getId()
{
return id;
}
public void setId(Long id)
{
this.id = id;
}
public Adress getAddress()
{
return adress;
}
public void setAddress(Adress adress)
{
this.adress = adress;
}
public String getFirstname()
{
return firstname;
}
public void setFirstname(String firstname)
{
this.firstname = firstname;
}
public String getLastname()
{
return lastname;
}
public void setLastname(String lastname)
{
this.lastname = lastname;
}
public String getEmail()
{
return email;
}
public void setEmail(String email)
{
this.email = email;
}
@Override
public boolean equals(Object obj)
{
if (this == obj)
{
return true;
}
if (!(obj instanceof User))
{
return false;
}
final User user = (User) obj;
return !(email != null ? !email.equals(user.email) : user.email != null);
}
@Override
public int hashCode()
{
return 29 * (email != null ? email.hashCode() : 0);
}
}
我的 persistence.xml：
<?xml version="1.0" encoding="UTF-8"?>
<persistence version="1.0" xmlns="http://java.sun.com/xml/ns/persistence">
<persistence-unit name="testPU" transaction-type="JTA">
<provider>org.hibernate.ejb.HibernatePersistence</provider>
<jta-data-source>jdbc/testdb</jta-data-source>
<properties>
<property name="hibernate.dialect" value="org.hibernate.dialect.PostgreSQLDialect"/>
<property name="hibernate.show_sql" value="true"/>
<property name="hibernate.transaction.factory_class" value="org.hibernate.transaction.JTATransactionFactory"/>
<property name="hibernate.hbm2ddl.auto" value="update"/>
<property name="hibernate.connection.autocommit" value="true"/>
</properties>
</persistence-unit>
</persistence>
编辑：我忘了提及，我已经使用了此线程中提供的信息：在 Glassfish 服务器上配置 Hibernate JPA 2.0 的学习资源 https://stackoverflow.com/questions/3609430/learning-resource-for-configuring-hibernate-jpa-2-0-on-glassfish-server
