所以我之前写过这个(在 php 中),但是每次我尝试 echo $test" 时,我只是返回资源 id 5。有谁知道如何从变量中实际打印出 mysql 查询?
$dave= mysql_query("SELECT order_date, no_of_items, shipping_charge, SUM(total_order_amount) as test FROM `orders` WHERE DATE(`order_date`) = DATE(NOW()) GROUP BY DATE(`order_date`)") or die(mysql_error());
print $dave;
这将打印出查询:
$query = "SELECT order_date, no_of_items, shipping_charge, SUM(total_order_amount) as test FROM `orders` WHERE DATE(`order_date`) = DATE(NOW()) GROUP BY DATE(`order_date`)";
$dave= mysql_query($query) or die(mysql_error());
print $query;
这将打印出结果:
$query = "SELECT order_date, no_of_items, shipping_charge, SUM(total_order_amount) as test FROM `orders` WHERE DATE(`order_date`) = DATE(NOW()) GROUP BY DATE(`order_date`)";
$dave= mysql_query($query) or die(mysql_error());
while($row = mysql_fetch_assoc($dave)){
foreach($row as $cname => $cvalue){
print "$cname: $cvalue\t";
}
print "\r\n";
}
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