iOS：如何检测摇动动作？

我将以下代码添加到我的 appDelegate.m

- (void)motionBegan:(UIEventSubtype)motion withEvent:(UIEvent *)event
{
}

- (void)motionEnded:(UIEventSubtype)motion withEvent:(UIEvent *)event
{
    if (motion == UIEventSubtypeMotionShake )
    {
        // User was shaking the device. Post a notification named "shake".
        [[NSNotificationCenter defaultCenter] postNotificationName:@"shake" object:self];
    }
}

- (void)motionCancelled:(UIEventSubtype)motion withEvent:(UIEvent *)event
{   
}

- (void)shakeSuccess
{
    // do something...
}

然后我补充道：

- (BOOL)application:(UIApplication *)application didFinishLaunchingWithOptions:(NSDictionary *)launchOptions
{
    // Override point for customization after application launch.
    // INIT THE BACKGROUND PATH STRING

    [self refreshFields];
    [self.window addSubview:navController.view];
    [self.window makeKeyAndVisible];
    ***[[NSNotificationCenter defaultCenter] addObserver:self selector:@selector(shakeSuccess) name:@"shake" object:nil];***

    return YES;
}

当我在 iPhone 上启动应用程序时，不会调用名为“shakeSuccess”的方法。 我应该怎么做才能在我的应用程序中实现此功能？ 任何想法？

这可能会帮助你...
https://stackoverflow.com/a/2405692/796103 https://stackoverflow.com/a/2405692/796103

他说你应该设置UIApplication's applicationSupportsShakeToEdit to YES。并重写 VC 中的 3 个方法：

-(BOOL)canBecomeFirstResponder {
    return YES;
}

-(void)viewDidAppear:(BOOL)animated {
    [super viewDidAppear:animated];
    [self becomeFirstResponder];
}

- (void)viewWillDisappear:(BOOL)animated {
    [self resignFirstResponder];
    [super viewWillDisappear:animated];
}

你的其余代码都很好。 （这-motionEnded:withEvent:)