可基于多列格式化

我正在使用该包formattable生成格式化表格。我发现了一个不错的资源在 R 中设置表格格式 http://www.r-bloggers.com/formatting-table-output-in-r/。但这里的箭头格式示例仅基于特定列。

我的要求是：假设我来自不同的城市，A 列和 B 列，其中 A 具有“树木数量”和“污染”两个级别的因子，而 B 是这些同比变化的百分比。因此，如果 A 列值“树木数量”增加（因为它是正数），我想用正绿色箭头格式化 B 列，如果污染减少，则用红色箭头格式化。

举个例子（信用：马库斯·格斯曼）从链接本身来看，即使更改

library(formattable)
DF <- data.frame(Ticker=c("", "", "", "IBM", "AAPL", "MSFT"),
             Name=c("Dow Jones", "S&P 500", "Technology", 
                    "IBM", "Apple", "Microsoft"),
             Value=accounting(c(15988.08, 1880.33, NA, 
                                130.00, 97.05, 50.99)),
             Change=percent(c(-0.0239, -0.0216, 0.021, 
                              -0.0219, -0.0248, -0.0399)))
DF
##   Ticker       Name     Value Change
## 1         Dow Jones 15,988.08 -2.39%
## 2           S&P 500  1,880.33 -2.16%
## 3        Technology        NA  2.10%
## 4    IBM        IBM    130.00 -2.19%
## 5   AAPL      Apple     97.05 -2.48%
## 6   MSFT  Microsoft     50.99 -3.99%
formattable(DF, list(
  Name=formatter(
    "span",
    style = x ~ ifelse(x == "Technology", 
                       style(font.weight = "bold"), NA)),
  Value = color_tile("white", "orange"),
  Change = formatter(
    "span",
    style = x ~ style(color = ifelse(x < 0 , "red", "green")),
    x ~ icontext(ifelse(x < 0, "arrow-down", "arrow-up"), x)))
)

基于文档?formatter:

formattable(DF, list(
  Name=formatter(
    "span",
    style = x ~ ifelse(x == "Technology", 
                       style(font.weight = "bold"), NA)),
  Value = color_tile("white", "orange"),
  Change = formatter(
    "span",
    style = ~ style(color = ifelse(Change < 0 & Ticker != "IBM", "red", "green")),
    ~ icontext(ifelse(Change < 0 & Name != "IBM", "arrow-down", "arrow-up"), Change)))
)

显然，x ~公式样式限制您只能使用右侧的变量本身。你必须切换到~然后在右侧显式写入列名称（而不是像x).