有没有办法模糊匹配或提供分数作为行值应与哪个 ID 或组关联的假设？

我有一个看起来像这样的数据集

structure(list(ID = c(1, 2, 3, 4, 5, 6, 7, 8, 9, 10), Date = c("2020-01- 
\n04", 
"2020-04-03", "2020-12-10", "2020-09-12", "2020-11-19", "2020-04- \n03", 
"2020-06-03", "2020-05-03", "2020-08-09", "2020-10-10"), Name = c("Jon", 
"Mike", "", "Rodney", "Jon", "Mike", "", "Ryan", "Ryan", "Ryan"
), Phone = c("555-555-5555", "123-456-7890", "123-456-7890", 
"333-333-3333", "", "123-456-7890", "098-765-4321", "", "", "444-444- 
\n4444"
), Email = c("[email protected]", "[email protected]", "[email protected]", 
"[email protected]", "", "", "", "[email protected]", "", "[email protected]"
), Address = c("123 Main Street", "456 Washingto Avenue", "", 
"16 Henderson St", "", "456 Washingto Avenue", "123 Lincoln Avenue", 
"123 Lincoln Avenue", "", "156 Jefferson Street"), Group = c("1", 
"2", "2", "3", "1", "2", "4", "4", "4", "5")), row.names = c(NA, 
-10L), class = c("tbl_df", "tbl", "data.frame"))

我想要获得一个如下所示的数据集（请注意，分数列中的数字并不完全是我想要的数字。我只是添加了数字作为占位符。我将允许该方法确定正确的分数计数。但是 1 应该参考满分。

structure(list(ID = c(1, 2, 3, 4, 5, 6, 7, 8, 9, 10), Date = c("2020-01- 
04", "2020-04-03", "2020-12-10", "2020-09-12", "2020-11-19", "2020-04- 
03", "2020-06-03", "2020-05-03", "2020-08-09", "2020-10-10"), Name = 
c("Jon", "Mike", "", "Rodney", "Jon", "Mike", "", "Ryan", "Ryan", "Ryan"
), Phone = c("555-555-5555", "123-456-7890", "123-456-7890", 
"333-333-3333", "", "123-456-7890", "098-765-4321", "", "", "444-444- 
4444"), Email = c("[email protected]", "[email protected]", "[email protected]", 
"[email protected]", "", "", "", "[email protected]", "[email protected]", 
"[email protected]"), Address = c("123 Main Street", "456 Washingto 
Avenue","", "16 Henderson St", "", "456 Washingto Avenue", "123 Lincoln 
Avenue", 
"123 Lincoln Avenue", "", "156 Jefferson Street"), Group = c("1", 
"2", "2", "3", "1", "2", "4", "4", "4", "5"), Score = c("1", 
"1", ".88", "1", ".96", ".96", "1", "1", ".25", "1")), row.names = c(NA, 
-10L), class = c("tbl_df", "tbl", "data.frame"))

“分数”栏中的数字是任意的。我可以根据模糊匹配过程的规则获取其他数字。我脑海中的想法是，根据长数据集，脚本发现有四个组。这些组对应于 1、2、3 和 4，分别指 Jon、Mike、Rodney 和 Ryan。请注意，Ryan 的得分为 0.25，因为它只包含他的姓名，而不包含电话或电子邮件等其他信息。该分数是组内的相对分数，而不是相对于整个数据集的分数。

一套完整的

Col<-("Name","Phone","Email","Address")

应该画出一个完美的近似值，没有争议。 4 中 3 的一组应该高于 4 中 2 的集合，依此类推。这个过程该如何进行呢？这可能吗？