Java 文档生成器为 Xml 字符串返回 null 文档

I have tried all possible answers https://stackoverflow.com/questions/33098082/passing-xml-string-as-document-returning-null on Stackoverflow but I can't get this resolved.

我有以下 xml 作为字符串：

private static final String xmlStr = "<parameters>\n" +
            "  <parameter>\n" +
            "    <name>emp</name>\n" +
            "    <keyvalue>John Smith</keyvalue>\n" +
            "  </parameter>\n" +
            "  <parameter>\n" +
            "    <name>age</name>\n" +
            "    <keyvalue>22</keyvalue>\n" +
            "  </parameter>\n" +
            "  <parameter>\n" +
            "    <name>Birth Date</name>\n" +
            "    <keyvalue>02/05/1978</keyvalue>\n" +
            "  </parameter>\n" +
            "  <parameter>\n" +
            "    <name>password</name>\n" +
            "    <keyvalue>ye63633</keyvalue>\n" +
            "  </parameter>\n" +
            "</parameters>";

参数可以替换为任何字符串（我尝试过但没有成功），以下代码返回空文档：

 DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();
            factory.setNamespaceAware(true);
            DocumentBuilder builder = factory.newDocumentBuilder();
            Document document = builder.parse(new ByteArrayInputStream(xmlStr.getBytes("UTF-8")));

我尝试用以下内容替换文档：

Document document = builder.parse(new InputSource(new StringReader(xmlStr)));//This used to work 2 weeks ago.

document一直返回空文档，我不知道我做错了什么。几周前，同样的代码还可以工作。

我正在使用Java 1.8！

我感谢您的帮助。

UPDATE:

这是采用上述内容的完整代码xmlStr并尝试访问员工的年龄。

private String getElementValue(String tagName, String xmlString) {

        try {

            DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();
            DocumentBuilder builder = factory.newDocumentBuilder();
            Document document = builder.parse(new InputSource(new StringReader(xmlString)));
            Element rootElement = document.getDocumentElement();

            NodeList list = rootElement.getElementsByTagName(tagName);

            if (list != null && list.getLength() > 0) {
                NodeList subList = list.item(0).getChildNodes();

                if (subList != null && subList.getLength() > 0) {
                    return subList.item(0).getNodeValue();
                }
            }
        } catch (ParserConfigurationException e) {
            e.printStackTrace();
        } catch (SAXException e) {
            e.printStackTrace();
        } catch (IOException e) {
            e.printStackTrace();
        }


        return null;
    }

根据评论，该文档根本不为空，但访问所需的 xml 标记时出现问题。所以代码NodeList list = rootElement.getElementsByTagName("age");大小为 0。即它根本不进入循环。

它似乎工作正常。后面添加的代码如下builder.parse，显示正在解析 XML：

System.out.println("Root element: " + document.getDocumentElement().getNodeName());
NodeList nodeList = document.getElementsByTagName("parameter");
for (int temp = 0; temp < nodeList.getLength(); temp++) {
    org.w3c.dom.Node node = nodeList.item(temp);
    System.out.println("\nCurrent element: " + node.getNodeName());
    if (node.getNodeType() == org.w3c.dom.Node.ELEMENT_NODE) {
        Element element = (Element) node;
        System.out.println("Name: " + element.getElementsByTagName("name").item(0).getTextContent());
        System.out.println("Key Value: " + element.getElementsByTagName("keyvalue").item(0).getTextContent());
    }
}

Output:

Root element: parameters

Current element: parameter
Name: emp
Key Value: John Smith

Current element: parameter
Name: age
Key Value: 22

Current element: parameter
Name: Birth Date
Key Value: 02/05/1978

Current element: parameter
Name: password
Key Value: ye63633