Python-从Excel文件读取时间时未获得正确的日期时间

我有一个 Excel 文件，其中有 3 列作为日期时间或日期或时间字段。我正在通过阅读它xlrd包裹，我有时间milliseconds我想当我尝试将其转换回日期时间时我得到了错误的结果。

我尝试将文件转换为csv以及。这也没有帮助，我得到了我无法理解的奇怪的日期时间格式。

这是我尝试过的xlrd格式。我更喜欢使用文件.xlrs扩展名作为输入，否则我必须将 excel 文件转换为.csv每次我得到一个新的输入文件时。

from xlrd import open_workbook
import os,pickle,datetime

def main(path, filename, absolute_path_organisation_structure):
    absolute_filepath = os.path.join(path,filename)

    wb = open_workbook(absolute_filepath)
    for sheet in wb.sheets():
        number_of_rows = sheet.nrows
        number_of_columns = sheet.ncols

        for row_index in xrange(1, sheet.nrows):
            row=[]
            for col_index in xrange(4,7): #4th and 6th columns are date fields
                row.append(sheet.cell(row_index, col_index).value)

            print(row)  #Relevant list formed with 4th, 5th and 6th columns
            print(datetime.datetime.fromtimestamp(float(row[0])).strftime('%Y-%m-%d %H:%M:%S'))


path = "C:\\Users\\***************\\NEW DATA"
MISfile  = "P2P_2015 - Copy.xlsx"
absolute_path_organisation_structure = "C:\\Users\\******************NEW DATA\\organisation.csv"
main(path, MISfile, absolute_path_organisation_structure)

Result:

[42011.46789351852, u'Registered', 42009.0]
1970-01-01 17:10:11
[42011.46789351852, u'Sent for CTG1 approval', 42010.0]
1970-01-01 17:10:11
[42011.46789351852, u'Sent back', 42010.0]
1970-01-01 17:10:11
[42011.46789351852, u'Registered', 42011.0]
1970-01-01 17:10:11
[42011.46789351852, u'Sent for CTG1 approval', 42011.0]
1970-01-01 17:10:11
[42011.46789351852, u'Sent for CTG2 approval', 42012.0]
1970-01-01 17:10:11
[42011.46789351852, u'CTG2 Approved', 42012.0]
1970-01-01 17:10:11
[42011.46789351852, u'Sent back', 42013.0]
1970-01-01 17:10:11
[42170.61667824074, u'Registered', 42144.0]
1970-01-01 17:12:50
[42170.61667824074, u'Registered', 42144.0]
1970-01-01 17:12:50
[42170.61667824074, u'Sent back', 42165.0]
1970-01-01 17:12:50
[42170.61667824074, u'Sent back', 42165.0]
1970-01-01 17:12:50
[42170.61667824074, u'Registered', 42170.0]
1970-01-01 17:12:50
[42170.61667824074, u'Registered', 42170.0]
1970-01-01 17:12:50

实际输入文件：（从Excel复制）

1/7/2015 11:13  Registered  1/5/2015 0:00
1/7/2015 11:13  Sent for CTG1 approval  1/6/2015 0:00
1/7/2015 11:13  Sent back   1/6/2015 0:00
1/7/2015 11:13  Registered  1/7/2015 0:00
1/7/2015 11:13  Sent for CTG1 approval  1/7/2015 0:00
1/7/2015 11:13  Sent for CTG2 approval  1/8/2015 0:00
1/7/2015 11:13  CTG2 Approved   1/8/2015 0:00
1/7/2015 11:13  Sent back   1/9/2015 0:00
6/15/2015 14:48 Registered  5/20/2015 0:00
6/15/2015 14:48 Registered  5/20/2015 0:00
6/15/2015 14:48 Sent back   6/10/2015 0:00
6/15/2015 14:48 Sent back   6/10/2015 0:00
6/15/2015 14:48 Registered  6/15/2015 0:00
6/15/2015 14:48 Registered  6/15/2015 0:00

为什么我无法正确读取日期？为什么它们不简单地以字符串形式出现以便我可以轻松地转换它们？

xldate_as_tuple(xldate, 日期模式) [#]

将 Excel 数字（假定表示日期、日期时间或时间）转换为适合提供给 datetime 或 mx.DateTime 构造函数的元组。

Source: http://www.lexicon.net/sjmachin/xlrd.html#xlrd.xldate_as_tuple-function http://www.lexicon.net/sjmachin/xlrd.html#xlrd.xldate_as_tuple-function

使用示例：如何使用“xlrd.xldate_as_tuple()” https://stackoverflow.com/questions/3727916/how-to-use-xlrd-xldate-as-tuple