我正在努力使Iteratee
结构通用,这样我就可以传入不同的解析函数并获得不同的Iteratee
。这是有效的非通用版本:
use std::io::{BufRead, BufReader};
use std::str::{from_utf8, Utf8Error};
#[derive(PartialEq, Debug)]
struct Cat<'a> {
name: &'a str,
}
fn parse<'a>(slice: &'a [u8]) -> Result<Cat<'a>, Utf8Error> {
from_utf8(slice).map(|name| Cat { name: name })
}
struct Iteratee<R>
where R: BufRead + Sized
{
read: R,
}
impl<R> Iteratee<R>
where R: BufRead + Sized
{
fn next<'a, F>(&'a mut self, fun: F)
where F: Fn(Option<Result<Cat<'a>, Utf8Error>>) -> () + Sized
{
let slice = self.read.fill_buf().unwrap();
fun(Some(parse(slice)))
// ^^^^^^^^^^^ How do I pull 'parse' up as a function of Iteratee
}
}
fn main() {
let data = &b"felix"[..];
let read = BufReader::new(data);
let mut iterator = Iteratee { read: read };
iterator.next(|cat| assert_eq!(cat.unwrap().unwrap(), Cat { name: "felix" }));
}
这是我尝试使其通用,但我无法构造IterateeFun
带有对函数的引用或传入闭包。
struct IterateeFun<R, P, T>
where R: BufRead + Sized,
P: Fn(&[u8]) -> (Result<T, Utf8Error>) + Sized
{
read: R,
parser: P,
}
impl<R, P, T> IterateeFun<R, P, T>
where R: BufRead + Sized,
P: Fn(&[u8]) -> (Result<T, Utf8Error>) + Sized
{
fn next<'a, F>(&'a mut self, fun: F)
where F: Fn(Option<Result<T, Utf8Error>>) -> () + Sized
{
let slice = self.read.fill_buf().unwrap();
fun(Some((self.parser)(slice)))
}
}
fn main() {
let data = &b"felix"[..];
let read = BufReader::new(data);
let mut iterator = IterateeFun {
read: read,
parser: parse, // What can I put here?
// I've tried a closure but then I get error[E0495]/ lifetime issues
};
iterator.next(|cat| assert_eq!(cat.unwrap().unwrap(), Cat { name: "felix" }));
}
我想知道如何将函数传递到如图所示的结构中。或者我应该将其作为一种特质?