1.4
∫
s
e
c
2
x
d
x
、
∫
c
s
c
2
x
d
x
\int sec^2xdx、\int csc^2xdx
∫sec2xdx、∫csc2xdx
∫
s
e
c
2
x
d
x
=
t
a
n
x
+
C
\int sec^2x dx =tanx + C
∫sec2xdx=tanx+C
∫
c
s
c
2
x
d
x
=
c
o
t
x
+
C
\int csc^2x dx =cotx + C
∫csc2xdx=cotx+C
1.5
∫
s
e
c
d
x
、
∫
c
s
c
d
x
\int secdx、\int cscdx
∫secdx、∫cscdx
∫
s
e
c
x
d
x
=
l
n
∣
s
e
c
x
+
t
a
n
x
∣
+
C
\int secxdx = ln|secx+tanx|+C
∫secxdx=ln∣secx+tanx∣+C
∫
c
s
c
x
d
x
=
l
n
∣
c
s
c
x
−
c
o
t
x
∣
+
C
\int cscxdx = ln|cscx-cotx|+C
∫cscxdx=ln∣cscx−cotx∣+C
1.6
∫
s
e
c
x
t
a
n
x
d
x
、
∫
c
s
c
x
c
o
t
x
d
x
\int secxtanxdx、\int cscxcotxdx
∫secxtanxdx、∫cscxcotxdx
∫
s
e
c
x
t
a
n
x
d
x
=
∫
s
i
n
x
c
o
s
2
x
d
x
=
s
e
c
x
+
C
\int secxtanxdx=\int \frac{sinx}{cos^2x}dx=secx+C
∫secxtanxdx=∫cos2xsinxdx=secx+C
∫
c
s
c
x
c
o
t
x
d
x
=
∫
c
o
s
x
s
i
n
2
x
d
x
=
c
s
c
x
+
C
\int cscxcotxdx=\int \frac{cosx}{sin^2x}dx=cscx+C
∫cscxcotxdx=∫sin2xcosxdx=cscx+C
2. 反三角函数
2.1 arcsinx、arctanx
2.2 arccosx
3. 代数
3.1
∫
1
1
−
x
2
d
x
\int \frac{1}{\sqrt{1-x^2}}dx
∫1−x21dx
∫
1
a
2
−
x
2
d
x
=
a
r
c
s
i
n
x
a
+
C
\int \frac{1}{\sqrt{a^2-x^2}}dx=arcsin\frac{x}{a}+C
∫a2−x21dx=arcsinax+C
3.2
∫
1
1
+
x
2
d
x
\int \frac{1}{1+x^2}dx
∫1+x21dx
∫
1
a
2
+
x
2
d
x
=
1
a
a
r
c
t
a
n
x
a
+
C
\int \frac{1}{a^2+x^2}dx=\frac{1}{a}arctan\frac{x}{a}+C
∫a2+x21dx=a1arctanax+C
3.3
∫
1
x
2
±
a
2
d
x
\int \frac{1}{\sqrt{x^2\pm a^2}}dx
∫x2±a21dx
∫
1
x
2
+
a
2
d
x
=
l
n
(
x
+
x
2
+
a
2
)
+
C
\int \frac{1}{\sqrt{x^2+a^2}}dx=ln(x+\sqrt{x^2+a^2})+C
∫x2+a21dx=ln(x+x2+a2)+C
∫
1
x
2
−
a
2
d
x
=
l
n
∣
x
+
x
2
−
a
2
∣
+
C
\int \frac{1}{\sqrt{x^2-a^2}}dx=ln|x+\sqrt{x^2-a^2}|+C
∫x2−a21dx=ln∣x+x2−a2∣+C
3.4
∫
1
x
2
−
a
2
d
x
\int \frac{1}{x^2- a^2}dx
∫x2−a21dx
∫
1
x
2
−
a
2
d
x
=
1
2
a
l
n
∣
x
−
a
x
+
a
∣
+
C
\int \frac{1}{x^2- a^2}dx=\frac{1}{2a}ln|\frac{x-a}{x+a}|+C
∫x2−a21dx=2a1ln∣x+ax−a∣+C
3.5
∫
a
2
−
x
2
d
x
\int \sqrt{a^2-x^2}dx
∫a2−x2dx
∫
a
2
−
x
2
d
x
=
a
2
2
a
r
c
s
i
n
x
a
+
1
2
x
a
2
−
x
2
+
C
\int \sqrt{a^2-x^2}dx=\frac{a^2}{2}arcsin\frac{x}{a}+\frac{1}{2}x\sqrt{a^2-x^2}+C
∫a2−x2dx=2a2arcsinax+21xa2−x2+C