列，宽度参数不起作用

我在工作中运行 REHL7column -V at column from util-linux 2.23.2

我有 csv 文件，其中包含一些带有长字符串的列。 我想将 csv 作为表格查看，并限制列宽，因为我 通常对抽查长字符串不感兴趣。

cat foo_bar.csv | column -s"," -t -c5

看来列宽不限于 10 个字符。 我想知道这是一个错误，还是我做错了并且看不到它？

测试输入，test.csv

co1,col2,col3,col4,col5
1,2,3,longLineOfTextThatIdoNotWantToInspectAndWouldLikeToLimit,5

运行我认为正确的命令：

cat test.csv | column -s"," -t -c5 

co1  col2  col3  col4 col5
1    2     3     longLineOfTextThatIdoNotWantToInspectAndWouldLikeToLimit  5

The −c or −−columns选项并不像您想象的那样执行。默认情况下，column查看所有行以找到最长的一行。如果column可容纳 2 个 这些线的宽度为 80，然后每 2 条线适合一条：

$ cat file
1 this is a short line
2 this is a short line
3 this line needs to be 39 or less char
4 this line needs to be 39 or less char

$ column file
1 this is a short line                  3 this line needs to be 39 or less char
2 this is a short line                  4 this line needs to be 39 or less char

$ column -x file
1 this is a short line                  2 this is a short line
3 this line needs to be 39 or less char 4 this line needs to be 39 or less char

如果你把-c低于 80，您获得的可能性就会降低 超过 1 列：

$ column -c70 file
1 this is a short line
2 this is a short line
3 this line needs to be 39 or less char
4 this line needs to be 39 or less char

所以，简单地说，column不能做你想做的事。 awk 可以这样做：

BEGIN {
  FS = ","
}
{
  for (x = 1; x <= NF; x++) {
    printf "%s%s", substr($x, 1, 5), x == NF ? "\n" : "\t"
  }
}

Result:

co1     col2    col3    col4    col5
1       2       3       longL   5